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PIT_PIT [208]
4 years ago
11

WILL GIVE 5 STARS!!!! HELP ASAP!!!!

Physics
1 answer:
Lady_Fox [76]4 years ago
8 0

Answer:

Mollusks

Explanation:

The shear concentration of fossilized mollusks can be explained by the ability of their shells which are comprised primarily of calcium, allowing the hard shells remain  and become fossilized long after the animal has decomposed.

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All ions are atoms with a (2 points)
Andrews [41]

This could be wrong but I am giving a decent suggestion: All ions are atoms with a negative charge.

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White light is an _____________ mixture of all the colors.<br> a) observable b) unequal c) equal
Musya8 [376]

Answer:

unequal

Explanation:

White light is a combination of all colors in the color spectrum.

6 0
3 years ago
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1500 kg wrecking ball traveling at a speed of 3.5 m/s hits a wall that does not crumble but is pushed back 75 cm. If the wreckin
Rudiy27

Answer:

The size of the force that pushes the wall is 12,250 N.

Explanation:

Given;

mass of the wrecking ball, m = 1500 kg

speed of the wrecking ball, v = 3.5 m/s

distance the ball moved the wall, d = 75 cm = 0.75 m

Apply the principle of work-energy theorem;

Kinetic energy of the wrecking ball = work done by the ball on the wall

¹/₂mv² = F x d

where;

F is the size of the force that pushes the wall

¹/₂mv² = F x d

¹/₂ x 1500 x 3.5² = F x 0.75

9187.5 = 0.75F

F = 9187.5 / 0.75

F = 12,250 N

Therefore, the size of the force that pushes the wall is 12,250 N.

7 0
3 years ago
A cool down is considered the activity performed
tangare [24]

did you mean what activities are performed during the cool down?

5 0
3 years ago
A 7 kg object attached to a horizontal string moves with constant speed in a circle on a frictionless horizontal surface. The ki
Marizza181 [45]

Answer:

Explanation:

Given

mass of object m=7 kg

kinetic Energy k=36\ J

Tension in string T=326\ N

mass is moving in a horizontal circle so tension is providing the centripetal acceleration

therefore T=\frac{mv^2}{r}----1

where r=radius of circle

kinetic energy of particle k=\frac{1}{2}mv^2----2

divide 1 and 2 we get

\frac{T}{k}=\frac{\frac{mv^2}{r}}{\frac{1}{2}mv^2}

\frac{T}{k}=\frac{2}{r}

r=\frac{2k}{T}=\frac{2\times 36}{326}

r=0.2208\ m

   

8 0
3 years ago
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