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blsea [12.9K]
3 years ago
8

What type of modulation is typically used by broadcasting stations to transmit pictures on television screens?

Physics
2 answers:
umka21 [38]3 years ago
4 0
Analog

Television transmitters use one of two different technologies: analog, in which the picture and sound are transmitted by analog signals modulated onto the radio carrier wave, and digital in which the picture and sound are transmitted by digital signals.
Naddika [18.5K]3 years ago
4 0

Answer:

A. Amplitude

Explanation:

The type of modulation that is typically used by broadcasting stations to transmit pictures on television screens is amplitude. Therefore, the answer to your question is A.

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The melting point of potassium thiocyanate determined by a student in the laboratory turned out to be 174.5 oC. The accepted val
yaroslaw [1]

Answer:

0.75%

Explanation:

Measured value of melting point of potassium thiocyanate = 174.5 °C

Actual value of melting point of potassium thiocyanate = 173.2 °C

<em>Error in the reading = |Experimental value - Theoretical value|</em>

<em>= |174.5 - 173.2|</em>

<em>= |1.3|</em>

<em>Percentage error = (Error / Theoretical value) × 100</em>

<em>= (1.3 / 173.2)×100</em>

<em>= 0.75 %</em>

∴ Percentage error in the reading is 0.75%

4 0
3 years ago
It took 1700 J of work to stretch a spring from its natural length of 2m to a length of 5m. Find the spring's force constant.
Alenkasestr [34]
The work to stretch a spring from its rest position is

               (1/2) (spring constant) (distance of the stretch)²

           E = 1/2 k x² .

You said it takes 1700 joules to stretch the spring 3 meters from its rest position, so we can write

                 1700 joules  =  1/2 k (3m)²

1 joule = 1 newton-meter

                 1700 N-m =  1/2 k  (3m)²

Multiply each side by 2:   3400 N-m  =  k · 9m²   

Divide each side by  9m²     k  =  3400 N-m / 9m²

                                                   =  (377 and 7/9)   newton per meter    

7 0
3 years ago
Read 2 more answers
A soccer player kicks a 0.44 kg ball with a force of 57.6 N, what is the ball’s acceleration
noname [10]

THE BALL'S ACCELERATION IS 130.90\frac{m}{s}

Explanation:

According to Newton's second law "the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)", meaning that when the soccer player kicks a ball, a force is acting on the ball, therefore increasing it's acceleration

SO FOR CALCULATING THIS WE WILL USE NEWTON LAW,

   FORCE = MASS × ACCELERATION

WE ARE GIVEN

FORCE = 57.6N

MASS= .44KG

SO HERE WE APPLYING FORMULA ,WE WILL GET

ACCELERATION = \frac{FORCE}{MASS}

ACCELERATION = \frac{57.6N}{.44KG}

ACCELERATION =130.90\frac{m}{s}

8 0
3 years ago
In the previous part, you determined the maximum angle that still allows the crate to remain at rest. If the coefficient of fric
lorasvet [3.4K]

Answer:

B. The maximum angle decreases

Explanation:

If θ be the maximum angle of a slope that allows a crate placed on it to remain at rest , following condition exists .

tanθ = μ , θ is called angle of repose . μ is coefficient of static friction .

So the tan of angle of repose θ is proportional to coefficient of static friction.

If coefficient of static friction is less than .7 , naturally angle of repose will also become less ,ie,  it at lower angle of inclination , the object will start slipping .

7 0
3 years ago
Accelerates uniformly at 2.0 ms2 for 10.0s. Calculate its final velocity​
Crazy boy [7]

Answer:

The distance is

=

7

m

Explanation:

Apply the equation of motion

s

(

t

)

=

u

t

+

1

2

a

t

2

The initial velocity is

u

=

0

m

s

−

1

The acceleration is

a

=

2

m

s

−

2

Therefore, when

t

=

3

s

, we get

s

(

3

)

=

0

+

1

2

⋅

2

⋅

3

2

=

9

m

and when

t

=

4

s

s

(

4

)

=

0

+

1

2

⋅

2

⋅

4

2

=

16

m

Therefore,

The distance travelled in the fourth second is

d

=

s

(

4

)

−

s

(

3

)

=

16

−

9

=

7

m

4 0
2 years ago
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