Answer:
B.
General Formulas and Concepts:
<u>Chemistry - Organic</u>
- Hydrocarbons
- Bond-Line Notation: Each "arrow" point represents a carbon and the lines represent a bond between the carbons. Hydrogens are assumed added when drawing the molecular formulas
Explanation:
We are given C₈H₁₈. We need a Bond-Line notation where there are 8 "arrow" points (which represent Carbon). We can disregard the Hydrogens as they are assumed to take the rest of the bonds.
Only option B has a value of 8 carbons, represented by the "arrow" points. Therefore, it is the correct answer.
Answer:
<h2>
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Explanation:
<em><u>In</u></em><em><u> </u></em><em><u>first</u></em><em><u> </u></em><em><u>picture</u></em><em><u>,</u></em>
When rock was not in the cylinder,
Volume of water
<em><u>In</u></em><em><u> </u></em><em><u>second</u></em><em><u> </u></em><em><u>picture</u></em><em><u>,</u></em><em><u> </u></em>
When rock is in the cylinder,
Volume of water
<em><u>Hence</u></em><em><u>,</u></em>
Volume of rock
Answer:
Moles NH₃: 0.0593
0.104 moles of N₂ remain
Final pressure: 0.163atm
Explanation:
The reaction of nitrogen with hydrogen to produce ammonia is:
N₂ + 3 H₂ → 2 NH₃
Using PV = nRT, moles of N₂ and H₂ are:
N₂: 1atmₓ3.0L / 0.082atmL/molKₓ273K = 0.134 moles of N₂
H₂: 1atmₓ2.0L / 0.082atmL/molKₓ273K = 0.089 moles of H₂
The complete reaction of N₂ requires:
0.134 moles of N₂ × (3 moles H₂ / 1 mole N₂) = <em>0.402 moles H₂</em>
That means limiting reactant is H₂. And moles of NH₃ produced are:
0.089 moles of H₂ × (2 moles NH₃ / 3 mole H₂) = <em>0.0593 moles NH₃</em>
Moles of N₂ remain are:
0.134 moles of N₂ - (0.089 moles of H₂ × (1 moles N₂ / 3 mole H₂)) = <em>0.104 moles of N₂</em>
And final pressure is:
P = nRT / V
P = (0.104mol + 0.0593mol)×0.082atmL/molK×273K / 5.0L
<em>P = 0.163atm</em>
The dichloromethane (DCM) has less density than water and also the polarity of water is much more than DCM. So the mixture of water and dichloromethane will always be a heterogeneous mixture. In the mixture dichloromethane will be always up of the water layer. The volume of the separatory funnel which contains the mixture of DCM and water must have to be more than the total volume of the liquids thus the volume of the funnel will be more than (50+50) = 100mL.
The caution have to consider during the separation are-
1. The separatory funnel have to shake well with lid and have to settle down for some times until the two liquid separated.
2. The lid should be open very slowly as the vapor pressure of DCM is more and it will float on the water.
3. After this the stopcock should be opened and slowly the water will come out first followed by DCM.
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