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borishaifa [10]
3 years ago
14

A beam of light is a mixture of plane polarized and unpolarized light. When it is sent through a polaroid sheet, it is found tha

t the transmitted intensity can be varied by a factor of 9 depending on the orientation of the polaroid. Find the relative intensities of the two components. A. 0.20 unpolarized, 0.80 plane polarized B. 0.25 unpolarized, 0.75 plane polarized C. 0.50 unpolarized, 0.50 plane polarized D. 0.60 unpolarized, 0.40 plane polarized E. 0.80 unpolarized, 0.20 plane polarized
Physics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

A. 0.20 unpolarized and 0.80 plane polarized.

Explanation:

After passing through polaroid sheet , unpolarised portion will get reduced by half . So this portion becomes .20/ 2 = 0.10

The polarized portion can face two situation depending upon the angle of the polaroid.

It may either be cut off to zero. So total intensity of transmitted light  wil be .10 + 0 = .10

It may or be passed fully . In that case total intensity of transmitted light will become 0 .10 +0.80 =0.90

Ratio of these two light of maximum and minimum intensity is 0.90 / 0.10 = 9.

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You observe a distant galaxy. You find that a spectral line of hydrogen that is shifted from its normal location in the visible
dimulka [17.4K]

Answer:

The galaxy is moving away from us

Explanation:

Galaxy refers to a system of millions or billions of stars accompanied by gas and dust such that they are held together as a result of gravitational attraction.

When we observe a distant galaxy, we find that a spectral line of hydrogen that is shifted from its normal location in the visible part of the spectrum into the infrared part of the spectrum.

It means that the galaxy is moving away from us.

6 0
3 years ago
Explain how the message is transmitted from the receiving neuron’s dendrites down the axon all the way to the axon terminal (ele
Vikki [24]

The vesicles release neurotransmitters. These cross the synapse and are accepted by the receptors in the dendrites of the next neuron.

Explanation:

An axon, or nerve fiber, is a long slender projection of a nerve cell, or neuron, that conducts electrical impulses away from the neuron's cell body. Axons are in effect the primary transmission lines of the nervous system, and as bundles they help make up nerves.

When an action potential reaches the axon terminal, it depolarizes the membrane and opens voltage-gated Na+ channels. Na+ ions enter the cell, further depolarizing the presynaptic membrane.

6 0
3 years ago
Which statement describes a surface wave?
nexus9112 [7]
The answer would be c because a surface wave travels between two different materials, like air and water.
8 0
2 years ago
Read 2 more answers
A short-wave radio antenna is supported by two guy wires, 155 ft and 175 ft long. Each wire is attached to the top of the antenn
Vladimir79 [104]

Answer:

163.8 ft

Explanation:

In triangle ABD

AB = 155 ft

Cos63 = \frac{BD}{AB} = \frac{BD}{155}\\BD = 155 Cos63 \\BD = 70.4 ft

Sin63 = \frac{AD}{AB} = \frac{AD}{155} \\AD = 166 Sin63\\AD = 148 ft

Using Pythagorean theorem in triangle ADC

AC^{2} = AD^{2} + DC^{2} \\175^{2} = 148^{2} + DC^{2} \\DC = 93.4 ft

d = distance between the anchor points

distance between the anchor points is given as

d = BD + CD = 70.4 + 93.4\\d = 163.8 ft

5 0
3 years ago
Read 2 more answers
f your risk-aversion coefficient is A = 4 and you believe that the entire 1926–2015 period is representative of future expected
siniylev [52]

Answer:

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

Explanation:

As the complete question is not given here ,the table of data is missing which is as attached herewith.

From the maximized equation of the utility function it is evident that

Weight=\frac{E_M-r_f}{A\sigma_M^2}

For the equity, here as

  • Weight is percentage of the equity which is to be calculated
  • {E_M-r_f} is the Risk premium whose value as seen from the attached data for the period 1926-2015 is 8.30%
  • A is the risk aversion factor which is given as 4.
  • \sigma_M is the standard deviation of the portfolio which from the data for the period 1926-2015 is 20.59

By substituting values.

Weight=\frac{E_M-r_f}{A\sigma_M^2}\\Weight=\frac{8.30\%}{4(20.59\%)^2}\\Weight=0.4894 =48.94\%

So the weight of equity is 48.94%.

Now the weight of T bills is given as

Weight_{T-Bills}=1-Weight_{equity}\\Weight_{T-Bills}=1-0.4894\\Weight_{T-Bills}=0.5105=51.05\%\\

So  the weight of T-bills is 51.05%.

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

7 0
2 years ago
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