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borishaifa [10]
3 years ago
14

A beam of light is a mixture of plane polarized and unpolarized light. When it is sent through a polaroid sheet, it is found tha

t the transmitted intensity can be varied by a factor of 9 depending on the orientation of the polaroid. Find the relative intensities of the two components. A. 0.20 unpolarized, 0.80 plane polarized B. 0.25 unpolarized, 0.75 plane polarized C. 0.50 unpolarized, 0.50 plane polarized D. 0.60 unpolarized, 0.40 plane polarized E. 0.80 unpolarized, 0.20 plane polarized
Physics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

A. 0.20 unpolarized and 0.80 plane polarized.

Explanation:

After passing through polaroid sheet , unpolarised portion will get reduced by half . So this portion becomes .20/ 2 = 0.10

The polarized portion can face two situation depending upon the angle of the polaroid.

It may either be cut off to zero. So total intensity of transmitted light  wil be .10 + 0 = .10

It may or be passed fully . In that case total intensity of transmitted light will become 0 .10 +0.80 =0.90

Ratio of these two light of maximum and minimum intensity is 0.90 / 0.10 = 9.

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Explanation:

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What is the angle of the 2nd order bright fringe produced by two slits that are 8.25x10-5m apart if the wavelength of the incide
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In order to calculate the angle, we can use the formula below for a constructive interference (the interference is constructive because the fringe is bright):

d\sin\theta=m\lambda

Where d is the distance between the slits, m is the order of the interference and lambda is the wavelength.

So, using d = 8.25 * 10^-5, m = 2 and lambda = 4.5 * 10^-7, we have:

\begin{gathered} 8.25\cdot10^{-5}\cdot\sin\theta=2\cdot4.5\cdot10^{-7}\\ \\ \sin\theta=\frac{9\cdot10^{-7}}{8.25\cdot10^{-5}}\\ \\ \sin\theta=1.091\cdot10^{-2}\\ \\ \theta=0.625° \end{gathered}

Therefore the correct option is the second one.

5 0
1 year ago
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