Answer:
The concentration of the chloride ion is 1.8 mM
Explanation:
Step 1: Data given
An aqueous solution contains 3.6 mM of total ions.
Step 2: The equation
NaCl(aq) → Na+(aq) + Cl-(aq) : two ions
Step 3: Calculate the concentration of the chloride ion
Two ions = 3.6 mM
Chloride ion = 3.6/2 mM= 1.8 mM
Sodium ion = 3.6/2 mM = 1.8 mM
The concentration of the sodium ions is 1.8 mM
The concentration of the chloride ion is 1.8 mM
The total concentration = 3.6 mM
