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grandymaker [24]
3 years ago
15

Two crates, A and B, sit at rest side by side on a frictionless horizontal surface. The crates have masses mA and mB. A horizont

al force F is applied to crate A and the two crates move off to the right. Draw the free-body diagram for crates A and B.
I have tried <--|----->; <--|-->; <-----|--> to no avail, they are all incorrect. Normal force up is equal to weight (gravity) force down so sum of vertical forces F = 0N. I know I am doing something wrong but cannot figure out what and the system does not point me in the write direction with each incorrect response.

Physics
1 answer:
lord [1]3 years ago
5 0

Answer:

Here's what I get  

Explanation:

The free-body diagram for Crate A has a vertical gravitational force Wa downward and a vertical normal force Na from the frictionless surface upward.

It also has the horizontal applied force F to the right and a horizontal force from Crate B to the left.

The diagram for Crate B has a vertical gravitational force Wb downward and a vertical normal force Nb upward. It also has the horizontal force from Crate A to the right,

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Rowenda is stopped on the side of the road. She then starts pedaling her bicycle for 15 seconds. Her final
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4 0
3 years ago
Joey, whose mass is m = 36 kg, stands at rest at the outer edge of a frictionless merry-go-round with the mass M = 300 kg and th
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Answer:

\omega=0.24\ rad.s^{-1}

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mass of person, m=36\ kg

mass of merry go-round, M=300\ kg

radius of merry go-round, R=2\ m

velocity of the person running, v=4\ m.s^{-1}

<u>We consider merry go-round as a ring:</u>

Now the moment of inertial of the ring is given as,

I=M.R^2

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I_p=m.R^2

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<u>Now according to the conservation of angular momentum:</u>

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\omega = angular velocity of the merry-go-round

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\omega=\frac{144}{1200} \times \frac{4}{2}

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