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3 years ago

Which chemical equation represents a redox reaction?

Chemistry

2 answers:

svet-max [94.6K]3 years ago

8 0

Hello. This question is incomplete. The full question is:

"Which chemical equation represents a redox reaction? A. Mg(ClO3)2 + 2HCl → MgCl2 + 2HClO3 B. CO + H2O → H2 + CO2 C. 2NH4NO3 + CuCl2 → 2NH4Cl + Cu(NO3)2 D. Na2SO3 + FeBr2 → 2NaBr + FeSO3 "

Answer:

B. CO + H2O → H2 + CO2

Explanation:

The reactions that involve loss and gain of electrons are called oxide-reduction reactions. In the oxidation reaction, electrons are lost, while the reduction reaction consists of gaining electrons.

Oxidation can occur in three circumstances: when oxygen is added to the substance, when a substance loses hydrogen or when the substance loses electrons. Example: fruit salads tend to darken when they come into contact with air, this is because oxygen acts to promote fruit oxidation. A tip to avoid this is to add lemon or orange juice, as the vitamin C present in citrus fruits prevents the oxidizing action of oxygen on the salad.

Reduction, in turn, is the reverse and also occurs in three ways: when a substance loses oxygen, when it gains hydrogen or when it gains electrons. Example: when the copper oxide (black) is placed in an appropriate apparatus (chamber) for its reduction to occur, the hydrogen gas comes in contact with the super heated copper oxide and, as a result, it loses oxygen and gradually goes away. turning pink as it is being reduced to copper.

An example of a redox reaction is CO + H2O → H2 + CO2

noname [10]3 years ago

5 0

Answer:

Assign oxidation numbers to all atoms in the equation.

Compare oxidation numbers from the reactant side to the product side of the equation.

The element oxidized is the one whose oxidation number increased.

Explanation:

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g 2BrO3- + 5SnO22-+ H2O5SnO32- + Br2+ 2OH- In the above reaction, the oxidation state of tin changes from to . How many electron

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Answer:

In the above reaction, the oxidation state of tin changes from 2+ to 4+.

10 moles of electrons are transferred in the reaction

Explanation:

Redox reaction is:

2BrO₃⁻ + 5SnO₂²⁻ + H2O ⇄ 5SnO₃²⁻ + Br₂ + 2OH⁻

SnO₂²⁻ → SnO₃²⁻

Tin changes the oxidation state from +2 to +4. It has increased it so this is the oxidation from the redox (it released 2 e⁻). We are in basic medium, so we add water in the side of the reaction where we have the highest amount of oxygen. We have 2 O on left side and 3 O on right side so we add 1 water on the right and we complete with OH⁻ in the opposite side to balance the H.

SnO₂²⁻ + 2OH⁻ → SnO₃²⁻ + 2e⁻ + H₂O <u>Oxidation</u>

BrO₃⁻ → Br₂

First of all, we have unbalance the bromine, so we add 2 on the BrO₃⁻. We have 6 O in left side and there are no O on the right, so we add 6 H₂O on the left. To balance the H, we must complete with 12OH⁻. Bromate reduces to bromine at ground state, so it gained 5e⁻. We have 2 atoms of Br, so finally it gaines 10 e⁻.

6H₂O + 10 e⁻ + 2BrO₃⁻ → Br₂ + 12OH⁻ <u>Reduction</u>

In order to balance the main reaction and balance the electrons we multiply (x5) the oxidation and (x1) the reduciton

(SnO₂²⁻ + 2OH⁻ → SnO₃²⁻ + 2e⁻ + H₂O) . 5

(6H₂O + 10 e⁻ + 2BrO₃⁻ → Br₂ + 12OH⁻) . 1

5SnO₂²⁻ + 10OH⁻ + 6H₂O + 10 e⁻ + 2BrO₃⁻ → Br₂ + 12OH⁻ + 5SnO₃²⁻ + 10e⁻ + 5H₂O

We can cancel the e⁻ and we substract:

12OH⁻ - 10OH⁻ = 2OH⁻ (on the right side)

6H₂O - 5H₂O = H₂O (on the left side)

2BrO₃⁻ + 5SnO₂²⁻ + H2O ⇄ 5SnO₃²⁻ + Br₂ + 2OH⁻

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