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anygoal [31]
3 years ago
12

One day, after much exercise, my friends and I were thirsty. Upon searching through the refrigerator, we found a variety of liqu

ids to drink: water, orange juice with extra pulp, milk with extra calcium added and iced tea. Use the following terms to label each of the italicized items listed above: element, compound, solution, colloid and suspension.
Chemistry
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

Water = compound, Orange juice with extra pulp = suspension, Milk = colloid, Calcium = Element, Iced tea = solution.

Explanation:

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What accelerates the protons in the LHC?
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Answer:

CERN uses a series of particle accelerators to accelerate protons to their end speeds in the LHC. The first accelerator is the linear accelerator Linac 2. At one end of Linac 2, hydrogen from a bottle is passed through an electric field to strip off the electrons, leaving positively charged protons.

Explanation:

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What type of attraction is the basis for hydrogen bonds (imf)?
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Hydrogen bonds are strong intermolecular forces created when a hydrogen atom bonded to an electronegative atom approaches a nearby electronegative atom. Greater electronegativity of the hydrogen bond acceptor will lead to an increase in hydrogen-bond strength.
I hope this helps
5 0
3 years ago
Boyles Law P1V1 = P2V2
arsen [322]

Answer:

A. The balloons will increase to twice their original volume.

Explanation:

Boyle's law states that the pressure exerted on a gas is inversely proportional to the volume occupied by the gas at constant temperature. That is:

P ∝ 1/V

P = k/V

PV = k (constant)

P = pressure, V = volume.

P_1V_1=P_2V_2

Let the initial pressure of the balloon be P, i.e. P_1=P, initial volume be V, i.e. V_1=V. The pressure is then halved, i.e. P_2=\frac{P}{2}

P_1V_1=P_2V_2\\\\P*V=\frac{P}{2} *V_2\\\\V_2=\frac{2*P*V}{P}\\\\V_2=2V

Therefore the balloon volume will increase to twice their original volume.

3 0
3 years ago
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

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