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Iteru [2.4K]
3 years ago
5

For most substances the distance between particles is smallest when the substance

Physics
1 answer:
Volgvan3 years ago
4 0
Particles are further apart in gasses which means there's a bigger distance between them, and there's a smaller distance between them in solid form. 
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Andrew pokes a marble, and the marble rolls down a ramp. The marble moves with speed. Which forces are acting on the marble in t
MissTica

Answer: Velocity, Gravity, and Momentum

8 0
3 years ago
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A baseball has a momentum of 6.0 kg m/s south and a mass of 0.15 kg. What is the baseball’s velocity? Show work
kupik [55]

Momentum of an object is defined as product of mass and velocity

so it is given as

P = m* v

here it is given that

mass = 0.15 kg

momentum = 6 kg m/s

so by plug in values in the above equation

6 = 0.15 * v

v = \frac{6}{0.15}

v = 40 m/s

so its speed will be 40 m/s

6 0
4 years ago
Can ya pls answer dis rq!
lana66690 [7]

Answer:

For vegetarians beans

Explanation:

Because it's plant protein and very proteinious

5 0
3 years ago
A real (non-Carnot) heat engine, operating between heat reservoirs at temperatures of and performs 4.1 kJ of net work, and rejec
Sati [7]
There are some missing data in the problem. The full text is the following:
"<span>A </span>real<span> (</span>non-Carnot<span>) </span>heat engine<span>, </span>operating between heat reservoirs<span> at </span>temperatures<span> of 710 K and 270 K </span>performs 4.1 kJ<span> of </span>net work<span>, and </span>rejects<span> 9.7 </span>kJ<span> of </span>heat<span>, in a </span>single cycle<span>. The </span>thermal efficiency<span> of a </span>Carnot heat<span> engine, operating between the same </span>heat<span> reservoirs, in percent, is closest to.."

Solution:
The efficiency of a Carnot cycle working between cold temperature </span>T_C and  hot temperature T_H is given by
\eta = 1 - \frac{T_C}{T_H}
and it represents the maximum efficiency that can be reached by a machine operating between these temperatures. If we use the temperatures of the problem, T_C=270 K and T_H=710 K, the efficiency is
\eta = 1 - \frac{270 K}{710 K}=0.62 = 62%

Therefore, the correct answer is D) 62 %.
6 0
3 years ago
consider the free-body diagram. if you want the box to move, the force applied while dragging must be greater than the
NeTakaya

Answer:

Force of static friction between the two surfaces

Explanation:

When two surfaces come into contact, they exert a force that resist the sliding of the two surfaces. This force is called static friction.

This force is given by the relation

                                       F_{s}=\mu_{s}\eta

Where,

                             μ - coefficient of static friction

                             η - normal force acting on the body

When a force acts on a body placed on a rough surface, it doesn't do any work if the applied force was less than the force of static friction.

So, in order to move the body, the applied force should be greater than the force of static friction.

6 0
3 years ago
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