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Alexxandr [17]
3 years ago
13

Programmed cell death is called ____________ . During programmed cell death, there is ____________ of DNA polymerase. Programmed

cell death results in digestion of the ____________ . Programmed cell death results in the initiation of cell membrane signals to attract ____________ . Programmed cell death ____________ proper development and ____________ harmful cells.
Physics
1 answer:
padilas [110]3 years ago
8 0

Answer:

  • Programmed cell death is called <u>Apoptosis</u> .
  • During programmed cell death, there is <u>destruction</u> of DNA polymerase.
  • Programmed cell death results in digestion of the <u>cytoskeleton</u> .
  • Programmed cell death results in the initiation of cell membrane signals to attract <u>phagocyctic cells</u>.
  • Programmed cell death <u>promotes</u> proper development and <u>removes</u> harmful cells.

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If a Nissan Titan has a mass of 2,300 kilograms how many grams is that
padilas [110]

It would be 2300000 grams.

6 0
3 years ago
A piece of wire 29 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
skelet666 [1.2K]

Answer:

Explanation:

Total length of the wire is 29 m.

Let the length of one piece is d and of another piece is 29 - d.

Let d is used to make a square.

And 29 - d is used to make an equilateral triangle.

(a)

Area of square = d²

Area of equilateral triangle = √3(29 - d)²/4

Total area,

A = d^{2}+\frac{\sqrt3}{4}\left ( 29-d \right )^{2}

Differentiate both sides with respect to d.

\frac{dA}{dt}=2d- \frac{\sqrt3}{4}\times 2(29-d)

For maxima and minima, dA/dt = 0

d = 8.76 m

Differentiate again we get the

\frac{d^{2}A}{dt^{2}}= + ve

(a) So, the area is maximum when the side of square is 29 m

(b) so, the area is minimum when the side of square is 8.76 m

8 0
2 years ago
Calculate the charge that flows through the cell in 1 minute. Each filament lamp has a power of 3 W and a resistance of 12 Ω
lapo4ka [179]

Answer:

24 Coulumbs

Explanation:

Given data

time= 1 minute= 6 seconds

P=2 W

R= 12 ohm

We know that

P= I^2R

P/R= I^2

2/12= I^2

I^2= 0.166

I= √0.166

I= 0.4 amps

We know also that

Q= It

substitute

Q= 0.4*60

Q= 24 Columbs

Hence the charge is 24 Coulumbs

5 0
2 years ago
Explain how surface and subsurface events are integral parts of the rock cycle.
vagabundo [1.1K]
Example of surface events are erosion and weathering. Erosion is the carrying of a particle from one place to the other and weathering is the breaking down of particles. These processes help in rock formation because this allows physical changes (grouping together or breaking down) on a certain substance. Subsurface events are those which happened underground such as the flow of underground water which subsequently allow the deposition of minerals, etc. 
3 0
3 years ago
Where are electrons located in an atom?
Scilla [17]

Answer:

B. Outside the nucleus.

Explanation:

Electrons orbit the nucleus of the atom.

7 0
1 year ago
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