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scoundrel [369]
3 years ago
6

Analysis of a reaction mixture showed that it had the composition 0.411 mol/L N2, 0.535 mol/L H2, and 0.118 mol/L NH3 at 800 K,

at which temperature Kc = 0.278 for N2(g) + 3 H2(g) ⇀↽ 2 NH3(g). Calculate the reaction quotient Qc .
Chemistry
1 answer:
WINSTONCH [101]3 years ago
4 0
Your answer is oxide,h2o, and 0.535
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Iron and oxygen form rust. How many moles of rust should be produced if 1
kakasveta [241]

Answer:

1.387 moles

Explanation:

Step 1:

The balanced equation for the reaction. This is illustrated below:

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Step 2:

Determination of the number of mole of Fe in 155.321g of Fe. This can be achieved by doing the following:

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Step 3:

Determination of the number of mole of rust (Fe2O3) produced. This is illustrated below:

From the balanced equation above,

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Therefore, 2.774 moles of Fe will produce = (2.774 x 2)/4 = 1.387 moles of Fe2O3.

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