Answer: in this ecosystem tuna fish are considered predators and small fishes are their prey.
Explanation: This is just an easy smart guess why? because the Tuna fish(predator) eat the small fishes(prey) as if what it looks like in the chart.
Im not sure about this question but i hope this helps
Celsius: -11.7
Kelvin: 261.5
Hope it helps! Please mark Brainliest! :)
Answer:
800 g
Explanation:
We can express the decay of I-37 using the formula:
- Final Mass = Initial Mass *
We <u>input the data</u>:
- 25 g = Initial Mass *
And <u>solve for Initial Mass</u>:
- 25 g = Initial Mass *
- 25 g = Initial Mass * 0.03125
Meaning that out 800 grams of I-37, only 25 will remain after 40.35 days.
<h3>a) <u>Answer;</u></h3>
A- 7.30 M
<h3><u>Explanation;</u></h3>
3.65 Sodium sulfate
Na2(SO4) dissociates to give sodium ions and sulfate ions.
Na2(SO4) → 2Na+ + SO₄²₋
Therefore, twice the concentration of sodium ions as far as molarity is concerned.
<em><u>Concentration of sodium ions = 3.65 × 2= 7.3 M</u></em>
<h3>b) <u> Answer;</u></h3>
B- 2.76 M
<h3><u>Explanation;</u></h3>
b) 1.38 M sodium carbonate
Sodium carbonate dissociates completely to yield Sodium ions and carbonate ions
Na₂CO₃ → 2Na+ + CO₃²₋
The concentration of sodium ions will be twice the concentration of initial compound since it has a ratio of two.
<em>Concentration of sodium ions = 1.38 ×2 </em>
<em> = 2.76 M</em>
<h3>
c) <u>
Answer;</u></h3>
<em>0.785 M</em>
<h3><u>
Explanation;</u></h3>
b) 0.785 sodium bicarbonate
Sodium bicarbonate dissociates completely to sodium ions and a bicarbonate ions.
NaHCO₃ →Na+ + HCO₃⁻
In this case the concentration of Na+ will be equal to the concentration of the original compound since they share the same ratio.
Thus; <em><u>Na+ concentration = 0.785 M</u></em>
I’ll get back to u on this