Question

0.22 L of HNO3 is titrated to equivalence using 0.10 L of 0.1 MNaOH. What is the concentration of the HNO3?

Answer 1

Answer:- Molarity of the acid solution is 0.045M.

Solution:- The balanced equation for the reaction of given acid and base is:

$HNO_3+NaOH\rightarrow NaNO_3+H_2O$

From the balanced equation, they react in 1:1 mol ratio. So, we could easily solve the problem using the equation:

$M_aV_a=M_bV_b$

where, $M_a$ is the molarity of acid, $M_b$ is the molarity of base, $V_a$ is the volume of acid and $V_b$ is the volume of base.

Let's plug in the given values in the equation:

$M_a(0.22L)=0.1M(0.10L)$

on rearranging the above equation:

$M_a=\frac{0.1M(0.10L)}{0.22L}$

$M_a$ = 0.045M

So, the molarity of the acid solution is 0.045M.