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3 years ago

Why is it important to listen to your body when playing sports

2 answers:

8 0

It is important to listen to your body to prevent injuries that can sometimes even be too big of a price to pay for victory. If you see that your body is struggling, or that your muscles and/or bones are straining/breaking, you definitely should take it easy so as to prevent injury.

natima [27]3 years ago

4 0

Answer and explanation;

Sports should not hurt. If you are in pain, there may be several reasons why that is. Pain occurs when something is wrong. Ignoring the pain is a serious mistake. Instead, listen to your body and accommodate your play to limit or avoid the pain. If that does not help, you should stop playing and rest or see a doctor.

The three most common dangerous condition in sports include overuse, overexertion, and incorrect technique. Overuse is caused by repetitive motion and is common in sports that require repeated movements, like tennis and pitching. Overexertion is pushing the body beyond one's physical ability. Lastly, using an incorrect technique usually goes unnoticed and results in pain. To avoid all these conditions it is important to listen to your body.

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What is the average acceleration of the object represented in the graph above over the 10 seconds? I know the answer isn’t C

polet [3.4K]

It's always a good idea to start with the definition of the thing you're trying to find.

This problem is just trying to find out whether you KNOW the definition of acceleration. You may know it, but you haven't used it yet.

Average acceleration = (change in velocity) divided by (total time).

Change in velocity = (end value) minus (start value)

Change in velocity = (20m/s) - 0

Change in velocity = 20 m/s

Time = 10 s

Average acceleration = (20m/s)/(10s)

Average acceleration = 2 m/s^2

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3 years ago

Read 2 more answers

Calculate the magnitude of the average gravitational force between earth and the moon

zepelin [54]

F = G mM / r^2, where
F = gravitational force between the earth and the moon, 
G = Universal gravitational constant = 6.67 x 10^(-11) Nm^2/(kg)^2, 
m = mass of the moon = 7.36 × 10^(22) kg 
M = mass of the earth = 5.9742 × 10^(24) and 
r = distance between the earth and the moon = 384,402 km 

F 
= 6.67 x 10^(-11) * (7.36 × 10^(22) * 5.9742 × 10^(24) / (384,402 )^2 
= 1.985 x 10^(26) N

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3 years ago

A flask containing argon gas is connected to an closed-ended mercury manometer. The closed end is under vacuum. If the mercury l

iogann1982 [59]

Answer:

230 torr

Explanation:

Given that

P = 230 mm of Hg

If argon gas and mercury is in equilibrium position then the pressure on the both side will be same .

As we know that

1 torr = 1 mm of Hg

So the pressure of the argon will be 230 torr .

Unit conversion

1 torr = 1 mm of Hg

1 bar = 100 KPa = 10⁵ Pa = 10⁵ N/m² = 0.1 MPa = 0.1 x 10⁶ Pa

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3 years ago

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Alika [10]

Answer:

Gravitational energy and kinetic energy

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3 years ago

Stan is driving north on his scooter at 8m/s, accelerates 11m/s (North) in 4s, drives a constant velocity for the next 15s, and

kow [346]

A) Acceleration: $a_1 = 0.75 m/s^2, a_2 = 0, a_3 = -1.57 m/s^2$

B) The total displacement is 209.5 m north

C) The average velocity is 8.06 m/s north

Explanation:

Acceleration is defined as:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time taken for the velocity to change from u to v

Here we have:

- In the first segment,

u = 8 m/s north

v = 11 m/s north

t = 4 s

So the acceleration is

$a_1 = \frac{11-8}{4}=0.75 m/s^2$ (north)

- In the second segment, Stan drives at a constant velocity: so the final velocity is equal to the initial velocity,

u = v

Therefore, the acceleration is zero: $a_2 = 0$

- In the third segment,

u = 11 m/s (north)

v = 0 (he comes to a stop)

t = 7 s

So the acceleration is

$a=\frac{0-11}{7}=-1.57 m/s^2$

And the negative sign means the acceleration is south, opposite to the direction of motion.

In a uniformly accelerated motion, the displacement can be calculated as:

$s=ut+\frac{1}{2}at^2$

where

u is the initial velocity

a is the acceleration

t is the time

- For the first segment, we have

$u = 0\\a = 0.75 m/s^2\\t=4 s$

So the displacement is

$s_1 = 0+\frac{1}{2}(0.75)(4)^2=6 m$

- For the second segment, we have

$u = 11 m/s\\a = 0\\t=15 s$

So the displacement is

$s_2 = (11)(15)+0=165 m$

- For the third segment, we have

$u = 11\\a = -1.57 m/s^2\\t=7 s$

So the displacement is

$s_3 = (11)(7)+\frac{1}{2}(-1.57)(7)^2=38.5 m$

So the total displacement is:

s = 6 m + 165 m + 38.5 m = 209.5 m

In the north direction (positive direction)

The average velocity is given by:

$v=\frac{d}{t}$

where

d is the total displacement

t is the total time

Here we have:

d = 209.5 m

t = 26 s

Therefore, the average velocity is

$v=\frac{209.5}{26}=8.06 m/s$ (north)

Learn more about accelerated motion:

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brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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4 years ago