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jok3333 [9.3K]
3 years ago
13

A 100.-kilogram cart accelerates at 0.50 meter per second squared west as a horse exerts a force of 60. Newtons west on the cart

. What is the magnitude of the force that the cart exerts on the horse?
Physics
2 answers:
Fed [463]3 years ago
5 0
The force exerted on the cart of the horse is equal to the force exerted by the horse on the cart, so its magnitude is 60N
12345 [234]3 years ago
4 0

Answer:

The magnitude of the force on the horse by the cart is 60 N.

Explanation:

Given that,

mass of cart = 100 kg

Acceleration of cart = 0.50 m/s²

Horse exerted force on a cart F= 60 N

The cart is moving by the force is defined as:

F' = ma

F' = 100\times0.50

F' = 50\ N

The cart is moving by the 50 N force.

But according to newton's third law,

Newton's third law is action reaction law.

When we exerted the force on the object then the object exerted same force but opposite direction.

Therefore,

A horse exerted the force on the cart and the cart exerted equal but opposite force on horse.

F=-F''

F = -60 N

So, The magnitude of the force is 60 N

Hence, The magnitude of the force on the horse by the cart is 60 N.

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Answer:

The answers are located in each of the explanations showed below

Explanation:

a)

(i) Surface Tension: The tensile force that causes this tension acts parallel to the surface and is due to the forces of attraction between the molecules of the liquid. The magnitude of this force per unit of length is called surface tension.

σ = F/l [N/m]

where:

F = force [N]

l = length [m]

σ = Surface Tension [N/m]

(ii) Frequency is the number of repetitions per unit of time of any periodic event.

f = 1/T [1/s] or [s^-1] or [Hz]

where:

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f = frecuency [Hz] or [hertz]

(iii) Each of the units will be shown for each variable

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a = accelertion [m/s^2]

s = displacement [m]

[\frac{m}{s} ]^{2} =[\frac{m}{s} ]^{2} + 2* [\frac{m}{s^{2} } ]*[m]\\

[\frac{m^2}{s^2} ] =[\frac{m^2}{s^2} ] +  [\frac{m^{2} }{s^{2} } ]

[\frac{m^2}{s^2} ]

b) To find the velocity we must derivate the function X with respect to t because this derivate will give us the equation for the velocity, it means:

v=\frac{dx}{dt} \\v = 0.75*2*t+5*t

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ii) replacing in the derivated equation.

v=1.5*(4)+5\\v=11[m/s]

iii) the average velocity is defined by the expresion v = x/t

v = \frac{x-x_{0} }{t-t_{0} } \\

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2

a) Pascal's principle or Pascal's law, where the pressure exerted on an incompressible fluid and in balance within a container of indeformable walls is transmitted with equal intensity in all directions and at all points of the fluid.

Therefore:

P1 = pressure at point 1.

P2 = pressure at point 2.

P1 = F1/A1

P2= F2/A2

\frac{F_{1} }{A_{1} }=\frac{F_{2}}{A_{2} }  \\F_{1}=A_{1}*(\frac{F_{2}}{A_{2} })

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Other examples of surface tension:

The mosquitoes that can sit on the water.

A clip on the water.

Some leaves that remain floating on the surface.

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