Question

How many moles of o2 are produced when 0.325 mol of ko2 reacts in this fashion?

Answer 1

Answer : The number of moles of $O_2$ produced are 0.244 moles.

Explanation :  Given,

Moles of $KO_2$ = 0.325 moles

The balanced chemical equation follows:

$4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2$

By Stoichiometry of the reaction:

As, 4 moles of $KO_2$ react to give 3 moles of $O_2$

So, 0.325 moles of $KO_2$ react to give $\frac{3}{4}\times 0.325=0.244$ moles of $O_2$

Therefore, the number of moles of $O_2$ produced are 0.244 moles.

Answer 2

Answer is: 0.244 moles of oxygen are produced.

Balanced chemical reaction: 4KO₂ + 2CO₂ → 2K₂CO₃ + 3O₂.
n(KO₂) = 0.325 mol.
From chemical reaction: n(KO₂) : n(O₂) = 4 : 3.
n(O₂) = 3 · 0.325 mol ÷ 4.
n(O₂) = 0.244 mol; amount of substance.
KO₂ is potassium superoxide, inorganic compound and it is used as oxygen generator in rebreathers, spacecraft andsubmarines.