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3 years ago

Which of the following helps to explain how hydraulic lifts work?

Physics

2 answers:

Gnesinka [82]3 years ago

8 0

Answer : C. Pascal's principle.

Explaination : Pascal's principle (well-known as Pascal's law) states that if a closed container contains a fluid at rest, then a small change in pressure at one side of the fluid is transmitted to each and every part of the fluid and also to the walls of the container without any loss. In a hydraulic lift, we need the same mechanism to work and so we take the help of Pascal's principle.

Hence, the correct option is C. Pascal's principle.

FromTheMoon [43]3 years ago

6 0

Answer:

Correct answer is C

Explanation:

Defination of Hydrollic lift:

A hydraulic lift is an example of multiplication of force by hydraulic press, A multiplication of force can be achieved by the application of fluid pressure according to Pascal's principle.

Pascal's principal:

According to Pascal's principle in a fluid inside a closed container, a pressure change in one part of fluid is transmitted without loss to every portion of the fluid and to the walls of the container.

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3 years ago

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Two subway stops are separated by 1210 m. If a subway train accelerates at 1.30 m/s2 from rest through the first half of the dis

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Answer:

Part 1) Time of travel equals 61 seconds

Part 2) Maximum speed equals 39.66 m/s.

Explanation:

The final speed of the train when it completes half of it's journey is given by third equation of kinematics as

$v^{2}=u^2+2as$

where

'v' is the final speed

'u' is initial speed

'a' is acceleration of the body

's' is the distance covered

Applying the given values we get

$v^2=0+2\times 1.30\times \frac{1210}{2}\\\\v^{2}=1573\\\\\therefore v=39.66m/s$

Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as

$v=u+at\\\\v=0+1.30\times t\\\\\therefore t=\frac{39.66}{1.30}=30.51seconds$

Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance

Thus total time of journey equals $T=2\times 30.51\approx61seconds$