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makkiz [27]
4 years ago
14

An object was dropped from the plane with 1000 km above the ground with a mass of 300 kg. Find the acceleration of the object ea

ch second until it reaches the ground.
Physics
1 answer:
Oxana [17]4 years ago
8 0

Answer:

9.8m/s^2

Explanation:

The acceleration due to gravity on earth is 9.8m/s^2 regardless of the mass of the object. This means, in the absence of air resistance, both a 3000 kg object and a 300 kg will accelerate at the same rate of 9.8m/s^2 towards  earth.

The reason the acceleration due to gravity is the same for all masses is that by grace of nature, the inertial mass m of the object from F= ma  equals the gravitational mass m from F =G \dfrac{mM}{R^2}, resulting

ma=G\dfrac{mM}{R^2}

\boxed{a=G\dfrac{M}{R^2}}

which is the acceleration that only depends on the mass of earth and its radius, and not on the mass of the object.

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Determine the MA based on the diagram below.
artcher [175]
There are two things that you should remember while dealing with the "Lever Mechanical Advantage" problems:

1) The Effort Arm;
2) The Resistance Arm.

Some books label the Effort Arm as in-lever arm and the Resistance Arm as out-lever arm. (Physics Jargon that you need to remember in order to solve problems)

The Effort Arm is that "part" of the lever where the force can be applied. The Resistance Arm is where some mass is placed. In the diagram, as you can see, the mass is placed on one arm of the lever. Therefore, it is the Resistance Arm.

Now the formula for the "Mechanical Advantage(MA)" is:
MA =  \frac{L_{e} }{ L_{r} }

Where L_{e} is the length of the Effort Arm(the subscript "e" stands for Effort), and L_{r} stands for the length of the Resistance Arm(here "r" stands for Resistance).

Plug in the values:

L_{e} = 15m.
L_{r} = 7m.

Therefore, L_{e} / L_{r} = 15/7 = 2.143 = MA

The correct answer is option C(2.14).

-i

3 0
4 years ago
Read 2 more answers
what happens to a circuits resistance, voltage, and current when you increase the diameter of the wire in the circuit?
zhannawk [14.2K]

Answer:

Option D.

Resistance (R) decreases

Voltage (V) is constant

Current (I) increases

Explanation:

We'll begin by writing an equation relating resistance and diameter of a wire. This is given below:

R = ρL/A ......... (1)

A = πr² (since the wire is circular in shape)

r = d/2

A = πr² = π(d/2)²

A = πd²/4

Substitute the value of A into equation 1

R = ρL/A

R = ρL ÷ A

R = ρL ÷ πd²/4

R = ρL × 4/πd²

R = 4ρL /πd²

Where:

R is the resistance of the wire.

ρ is the resistivity of the wire.

L is the length of the wire.

A is the cross sectional area of the wire.

r is the radius.

d is the diameter of the wire

From equation (1) above, we can say that the resistance (R) is inversely proportional to the square of the diameter of the wire. This implies that an increase in the diameter of the wire will result in a decrease of the resistance. Also, a decrease in the diameter of the wire will result in an increase in the resistance of the wire.

1. Since the diameter of the wire is increase, therefore, the resistance of the wire will decrease.

2. From ohm's law,

V = IR

Divide both side by I

R = V/I

Where:

R is the resistance

V is the voltage

I is the current

From the above equation, the resistance (R) is directly proportional to the voltage (V) and inversely proportional to the current (I).

If we keep the voltage constant, this means that an increase in the resistance will lead to a decrease in the current. Also, a decrease in the resistance will lead to an increase in the current.

Since the resistance of the wire decrease, the current will increase.

From the illustrations made above, an increase in the diameter of the wire will lead to:

1. Decrease in resistance.

2. Voltage is constant.

3. Increase in current.

5 0
4 years ago
28.25 mL, three signicant digits
Mazyrski [523]

Answer:3) variable affinities (stickiness) for something it is running past. Physical ... -measurement number (significant digits) unit (such as inches) -Significant ... Mass 1 oz. 28.25 g. Relations Between English and Metric Units Mass 1 dram. 1.772 g ... -graduated cylinder has an error of about 1% (± 0.1 mL in 10 mL). -Volumetric

Explanation:

3 0
3 years ago
Read 2 more answers
How does reverberation explain why your voice sounds different in a gym than it does in your living room
TEA [102]
Sound can reach the inner ear by way of two separate paths, and those paths in turn affect what we perceive. Air-conducted sound is transmitted from the surrounding environment through the external auditory canal, eardrum and middle ear to the cochlea, the fluid-filled spiral in the inner ear. Bone-conducted sound reaches the cochlea directly through the tissues of the head.
When you speak, sound energy spreads in the air around you and reaches your cochlea through your external ear by air conduction. Sound also travels from your vocal cords and other structures directly to the cochlea, but the mechanical properties of your head enhance its deeper, lower-frequency vibrations. The voice you hear when you speak is the combination of sound carried along both paths. When you listen to a recording of yourself speaking, the bone-conducted pathway that you consider part of your “normal” voice is eliminated, and you hear only the air-conducted component in unfamiliar isolation. You can experience the reverse effect by putting in earplugs so you hear only bone-conducted vibrations.
Some people have abnormalities of the inner ear that enhance their sensitivity to this component so much that the sound of their own breathing becomes overwhelming, and they may even hear their eyeballs moving in their sockets.
6 0
3 years ago
You move a 75-kg box 35 m. This requires a force of 90 N. how much work is done while moving the box?
Luda [366]
W = F*d.

= 90*35 = 3150J.
4 0
3 years ago
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