For a Rectangular plate has a voltage of +180V and a 'voltage of -5V. , the second plate has the Electric field mathematically given as
E=21.5*10^3v/m
<h3>What is
the field strength?</h3>
Generally, the equation for the Electric field is mathematically given as
E=v/d
Where
v={180-(-5)}v
v=185v
Therefore
E=185/8.6*10^{-3}
E=21.5*10^3v/m
In conclusion, Electric field
E=21.5*10^3v/m
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Work = force in the direction of the movement x distance = 27 N x 1.7 m
Work = 45.9 joules
Answer: option c.
Answer:
<em>D. The acceleration after it leaves the hand is 10 m/s/s downwards
</em>
Explanation:
<u>Vertical Throw
</u>
When an object is thrown upwards, it describes a special type of motion ruled only by gravity.
When the ball is launched, it has its maximum speed upwards. The acceleration of gravity is always the same because it's a constant value near our planet's surface. The object starts to lose speed since the acceleration of gravity is pointed downwards and makes the object stop in the mid-air at its maximum height, where the speed is zero. Then, the object starts to fall and regain speed, this time downwards until it reaches back the launching point at the very same speed it was launched, but in the opposite direction.
The time it takes to reach its maximum height is the same it takes to return to the catching point, 2 seconds later.
With all these concepts in mind, we state that:
<em>D. The acceleration after it leaves the hand is 10 m/s/s downwards </em>
The other options are not correct because:
A. The acceleration is never upwards
B. The acceleration is never 0
C. Both times are equal
