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nikitadnepr [17]
3 years ago
13

An ideal fluid flows through a pipe made of two sections with diameters of 1.0 and 3.0 inches, respectively. The speed of the fl

uid flow through the 3.0-inch section will be what factor times that through the 1.0-inch section
Engineering
1 answer:
geniusboy [140]3 years ago
5 0

Answer:

(\frac{r_1}{r_2})^2=\frac{1}{9}

Explanation:

From the question we are told that:

Diameter 1 d_1=1.0

Diameter 2 d_2=3.0

Generally the equation for Radius is mathematically given by

At Diameter 1

r_{1}=\frac{1}{2} inch

At Diameter 2

r_{2}=\frac{3}{2} inch

Generally the equation for continuity is mathematically given by

 A_1V_1=A_2V_2

Therefore

(\frac{r_1}{r_2})^2=(\frac{1/2}{3/2})^2

(\frac{r_1}{r_2})^2=\frac{1}{9}

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