Match each physical property of matter to the appropriate definition
2 answers:
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Answer:
f = 931.1 Hz
Explanation:
Given,
Mass of the wire, m = 0.325 g
Length of the stretch, L = 57.7 cm = 0.577 m
Tension in the wire, T = 650 N
Frequency for the first harmonic = ?
we know,
μ is the mass per unit length
μ = 0.325 x 10⁻³/ 0.577
μ = 0.563 x 10⁻³ Kg/m
now,
v = 1074.49 m/s
The wire is fixed at both ends. Nodes occur at fixed ends.
For First harmonic when there is a node at each end and the longest possible wavelength will have condition
λ=2 L
λ=2 x 0.577 = 1.154 m
we now,
v = f λ
f = 931.1 Hz
The frequency for first harmonic is equal to f = 931.1 Hz
Answer:
C. The spring constant of spring 2 is larger than spring 1.
Explanation:
As we know that spring constant also called the stiffness constant of a spring is the value of force required for the deformation of the spring by a unit length.
Mathematically given as:
where:
stiffness constant
force on the spring
change in length of the spring
It is given in the question that spring 1 is easily compressible and requires less force to compress as compared to spring 2 and hence it has lesser stiffness constant than that of spring 2.