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yuradex [85]
4 years ago
7

As a student in a physics lab, you are asked to classify two springs. Right away you notice some differences. The first spring,

spring 1, is very easy to compress and pliable. The second spring, spring 2, is stiffer and more difficult to deform. What qualitative statement can you make about their spring constants?
A. No inference can be made, the student needs to take a measurement.
B. The spring constant of spring 1 is larger than spring 2.
C. The spring constant of spring 2 is larger than spring 1.
D. The spring constants are the same because spring 1 has more displacement, while spring 2 requires more force.
Physics
1 answer:
strojnjashka [21]4 years ago
3 0

Answer:

C. The spring constant of spring 2 is larger than spring 1.

Explanation:

As we know that spring constant also called the stiffness constant of a spring is the value of force required for the deformation of the spring by a unit length.

Mathematically given as:

k=\frac{F}{\delta x}

where:

k= stiffness constant

F= force on the spring

\delta x= change in length of the spring

It is given in the question that spring 1 is easily compressible and requires less force to compress as compared to spring 2 and hence it has lesser stiffness constant than that of spring 2.

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A motorcyclist heading east through a small town accelerate at constant 4.0meter per seconds square after he leaves the limits.
SVETLANKA909090 [29]

A) The position at t = 2.0 sec is 43.0 m east

B) The position is 55 m east

Explanation:

A)

In order to solve the problem, we take the east direction as positive direction.

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- at t = 0, the initial velocity of the motorcyclist is v_0 = 15.0 m east

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B)

The velocity of the motoryclist can be found by calculating the derivative of the position. Therefore, it is:

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Solving the equation for t,

t=\frac{v-v_0}{a}=\frac{25-15}{4}=2.5 s

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Learn more about accelerated motion:

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