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yuradex [85]
3 years ago
7

As a student in a physics lab, you are asked to classify two springs. Right away you notice some differences. The first spring,

spring 1, is very easy to compress and pliable. The second spring, spring 2, is stiffer and more difficult to deform. What qualitative statement can you make about their spring constants?
A. No inference can be made, the student needs to take a measurement.
B. The spring constant of spring 1 is larger than spring 2.
C. The spring constant of spring 2 is larger than spring 1.
D. The spring constants are the same because spring 1 has more displacement, while spring 2 requires more force.
Physics
1 answer:
strojnjashka [21]3 years ago
3 0

Answer:

C. The spring constant of spring 2 is larger than spring 1.

Explanation:

As we know that spring constant also called the stiffness constant of a spring is the value of force required for the deformation of the spring by a unit length.

Mathematically given as:

k=\frac{F}{\delta x}

where:

k= stiffness constant

F= force on the spring

\delta x= change in length of the spring

It is given in the question that spring 1 is easily compressible and requires less force to compress as compared to spring 2 and hence it has lesser stiffness constant than that of spring 2.

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A car of mass M = 1000 kg traveling at 50.0 km/hour enters a banked turn covered with ice. The road is banked at an angle θ , an
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The radius of the curved road at the given condition is 54.1 m.

The given parameters:

  • <em>mass of the car, m = 1000 kg</em>
  • <em>speed of the car, v = 50 km/h = 13.89 m/s</em>
  • <em>banking angle, θ = 20⁰</em>

The normal force on the car due to banking curve is calculated as follows;

Fcos(\theta) = mg

The horizontal force on the car due to the banking curve is calculated as follows;

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<em>Divide </em><em>the second equation by the first;</em>

\frac{Fsin(\theta)}{Fcos(\theta) } = \frac{mv^2}{rmg} \\\\tan(\theta) = \frac{v^2}{rg} \\\\r = \frac{v^2}{g \times tan(\theta)} \\\\r = \frac{13.89^2}{9.8 \times tan(20)} \\\\r = 54.1 \ m

Thus, the radius of the curved road at the given condition is 54.1 m.

Learn more about banking angle here: brainly.com/question/8169892

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What do we call the principal SI units that are used to derive all other SI units? Question 3 options:
Angelina_Jolie [31]

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Answer:

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Explanation:

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Answer:

Yeah ice floats on water.

Observation

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