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2 years ago

How can you degauss a magnet temporarily?

Physics

1 answer:

EleoNora [17]2 years ago

7 0

Answer:

Demagnetization processes include heating past the Curie point, applying a strong magnetic field, applying alternating current, or hammering the metal.

Explanation:

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Wich of the following celestial bodies is most likely to have many craters

Ede4ka [16]

Where are the following awnsers?

6 0

2 years ago

A 1.0-kg ball is attached to the end of a 2.5-m string to form a pendulum. This pendulum is released from rest with the string h

hram777 [196]

Answer:

$v_{2}=3.5 m/s$

Explanation:

Using the conservation of energy we have:

$\frac{1}{2}mv^{2}=mgh$

Let's solve it for v:

$v=\sqrt{2gh}$

So the speed at the lowest point is $v=7 m/s$

Now, using the conservation of momentum we have:

$m_{1}v_{1}=m_{2}v_{2}$

$v_{2}=\frac{1*7}{2}$

Therefore the speed of the block after the collision is $v_{2}=3.5 m/s$

I hope it helps you!

8 0

3 years ago

Water is contained in a closed, rigid 0.2 m 3 tank at an initial pressure of 5 bar and a quality of 50%. Heat transfer occurs un

elena55 [62]

Answer:

Final mass=0.89kg

Final pressure=5.6bar

Explanation:

To find mass,m=v/v1

But v1=vf + x(vg-vf)

Vf= 0.001093m^3/kg

Vg= 0.3748m^3/kg

V1= 0.001093+0.5(0.3748-0.001093)

V1= 0.225m^3/kg

M= 0.20/0.225 =0.89kg

Final pressure will be:

V/V1= P/P1

Cross multiply

VP1=V1P

P1= 0.225×5/0.2

P1=:5.6 bar

7 0

3 years ago

What force is used to make the back-and-forth motion of a swing higher?

Eddi Din [679]

Answer:

its a

Explanation:

scrape - push or pull a hard or sharp implement across (a surface or object) so as to remove dirt or other matter.

5 0

2 years ago

Read 2 more answers

Density of water 1000kgper m^3 What will be the volume of 3500 kg water

skad [1K]

Answer:

The volume of water is 3.5 cubic meter

Explanation:

Density

The density of a substance or material is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

$\displaystyle \rho=\frac{m}{V}$

We are given the density of water as $\rho=1,000\ kg/m^3$ .It's required to find the volume of m=3,500 kg of water. Solving for V:

$\displaystyle V=\frac{m}{\rho}$

$\displaystyle V=\frac{3,500}{1,000}$

$V=3.5\ m^3$

The volume of water is 3.5 cubic meter

5 0

2 years ago