All categories

2 years ago

(Please help 15 points the assignment is late) (multiple questions) (everything is virtual task )

Physics

1 answer:

krok68 [10]2 years ago

5 0

Answer:

i & 2

Explanation:

U alr finished it so there's no point

You might be interested in

One end of a spring with a force constant of k = 10.0 N/m is attached to the end of a long horizontal frictionless track and the

koban [17]

Answer:

-2.478

0.379

11.14

24.78

Explanation:

Angular frequency of spring in harmonic motion is given by?

ω = √(k/m)

ω = √(10/2.2)

ω = √4.54

ω = 2.13 s^-1

If at t=0 the mass is in negative amplitude (x = -A = -2.48 m) then we describe the position with negative cosine

x(t) = -A * cos(ωt)

x(t) = -2.48 * cos(2.13 * 1)

x(t) = -2.48 * 0.9993

x(t) = -2.478

Velocity and acceleration are 1st and 2nd derivative of position

v(t) = Aω * sin(ωt)

v(t) = 2.48 * 2.13 * sin(2.13 * 1)

v(t) = 5.282 * sin2.13

v(t) = 5.282 * 0.03717

v(t) = 0.379 m/s

a(t) = Aω^2 * cos(ωt)

a(t) = 2.48 * 2.12² * cos(2.13 * 1)

a(t) = 2.48 * 4.494 * cos2.13

a(t) = 11.15 * 0.9993

a(t) = 11.14 m/s²

F = -k * x(t)

F = -10 * -2.478

F = 24.78 N

3 0

3 years ago

Velocity answer. please explain steps

spin [16.1K]

As it is a position time graph

So, it's slope represents velocity

During last 15 seconds

it passes through (5,17) (20,2)

Slope = -15/15 = -1

So Velocity= -1 m/s

5 0

3 years ago

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin

gogolik [260]

Answer:

$7.54\cdot 10^{-7} C$

Explanation:

The capacitance of a parallel-plate capacitor is given by

$C=\frac{\epsilon_0 A}{d}$

where $\epsilon_0$ is the vacuum permittivity, A is the surface area of the plates, d their separation.

We also know the following relationship

$C=\frac{Q}{V}$

where Q is the charge stored on the capacitor and V the potential difference between the plates.

Combining the two equations,

$\frac{\epsilon_0 A}{d}=\frac{Q}{V}$

We also know that for a uniform electric field (such as the one between the plates of a parallel-plate capacitor), we have

$V= Ed$

where E is the magnitude of the electric field. Substituting into the previous equation and re-arranging it,

$\frac{\epsilon_0 A}{d}=\frac{Q}{Ed}\\Q=\frac{\epsilon_0 A E d}{d}=\epsilon_0 A E$

For the capacitor in the problem:

$A=\pi r^2 = \pi (\frac{d}{2})^2 = \pi (\frac{0.19 m}{2})^2=0.0284 m^2$ is the area of the plates

$E=3\cdot 10^6 N/C$ is the maximum electric field before a spark is produced

Solving for Q, we find the maximum charge that can be added before that occurs:

$Q=(8.85\cdot 10^{-12})(0.0284)(3\cdot 10^6)=7.54\cdot 10^{-7} C$

3 0

3 years ago

Please... what are the differences between alternators and generators

astraxan [27]

The difference between them is in regard to what spins and what is fixed. In an alternator<span>, electricity is produced when a magnetic field spins inside the stator (windings of wired) </span>

7 0

3 years ago

What is not a recognized swimming stroke A. dog paddle B. butterfly C. breast stroke D. backstroke

scZoUnD [109]

The awnser is C. Breast stroke Hope this helps :)

4 0

3 years ago

Read 2 more answers