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ohaa [14]
3 years ago
14

Both the electrical force and the gravitational force between two objects share which relationship?

Physics
2 answers:
love history [14]3 years ago
8 0

Answer : They are inversely proportional to the square of the distance.

Explanation :

We know that the electrical or electrostatic force is given by :

F=\dfrac{1}{4\pi \epsilon_0}\dfrac{q_1q_2}{r^2}.........(1)

Where,

\dfrac{1}{4\pi \epsilon_0} is constant

q_1 q_2 are the electric charges,

r is the distance between two charges.

Similarly, the gravitational force is given by :

F=G\dfrac{m_1m_2}{r^2}..........(2)

Where

G is the universal gravitational constant

m_1 and m_1  are the masses

r is the distance between them

From equation (1) and (2), it is clear that the both electrical as well as gravitational forces are inversely proportional to the square of the distance between them.    

Hence, the correct option is (b) " They are inversely proportional to the square of the distance" .

kolbaska11 [484]3 years ago
7 0

They are inversely proportional to the square of the distance.

Explanation:

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the two objects.

The magnitude of the electrical force between two objects is given by

F=k\frac{q_1 q_2}{r^2}

where k is the Coulomb's constant, q1 and q2 are the charges of the two objects, and r is the distance between the two objects.

In both cases, we see that the magnitude of the force is iinversely proportional to the square of the distance, \frac{1}{r^2}, so the correct option is

They are inversely proportional to the square of the distance.

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Consider a lawnmower of mass m which can slide across a horizontal surface with a coefficient of friction μ. In this problem the
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Answer:

Fh = u*m*g / (cos(θ) - u*sin(θ))

Explanation:

Given:

- The mass of lawnmower = m

- The angle the handle makes with the horizontal = θ

- The force applied along the handle = Fh

- The coefficient of friction of the lawnmower with ground = u

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Find the magnitude, Fh, of the force required to slide the lawnmower over the ground at constant speed by pushing the handle.

Solution:

- Construct a Free Body Diagram (FBD) for the lawnmower.

- Realize that there is horizontal force applied parallel to ground due to Fh that drives the lawnmower and a friction force that opposes this motion. We will use to Newton's law of motion to express these two forces in x-direction as follows:

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- Since, the lawnmower is to move with constant speed then we have a = 0.

                                     F_net,x = 0

- The forces as follows:

                                     Fh*cos(θ) - Ff = 0

Where, Ff is the frictional force:

                                     Fh = Ff /cos(θ)

Similarly, for vertical direction y the forces are in equilibrium. Using equilibrium equation in y direction we have:

                                    - W - Fh*sin(θ) + Fn = 0

Where, W is the weight of the lawnmower and Fn is the contact force exerted by the ground on the lawnmower. Then we have:

                                     Fn = W + Fh*sin(θ)

                                     Fn = m*g + Fh*sin(θ)

The Frictional force Ff is proportional to the contact force Fn by:

                                     Ff = u*Fn

                                     Ff = u*(m*g + Fh*sin(θ))

Substitute this expression in the form derived for Fh and Ff:

                                     Fh*cos(θ) = u*(m*g + Fh*sin(θ))

                                     Fh*(cos(θ) - u*sin(θ)) = u*m*g

                                     Fh = u*m*g / (cos(θ) - u*sin(θ))

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