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Keith_Richards [23]
3 years ago
15

How many moles of sodium hydroxide are required to react completely with 23.1 moles of sulfuric acid

Chemistry
2 answers:
Natalka [10]3 years ago
4 0

Answer:

46.2 moles

Explanation:

Since 2 moles of NaOH is required to completely neutralize sulphuric acid to form a normal salt and 1 mole of sulphuric acid is required in the reaction. So if 1 mole of sulphuric acid is 23.1, then 2 moles of NaOH would be 46.2.

A chemical balanced equation is written below

H2SO4 + 2NaOH = Na2SO4 + 2H2O

almond37 [142]3 years ago
3 0

Answer:

46. 2 moles of NaOH

Explanation:

Balanced chemical equation between sodium hydroxide and sulfuric acid

2NaOH + H2SO4 = Na2SO4 + 2H2O

I mole of sulphuric acid is neutralized by = 2 moles of NaOH

23.1 mole of sulphuric acid is neutralized by = 2 x 23.1

                                                                       = 46. 2 moles of NaOH

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How many grams are in 11.9 moles of chromirum
faust18 [17]

Answer:

Explanation:

Method 1 proportion

1 mole of chromium is 52 grams

11.9 moles = x grams

1/11.9 = 52/x                    Cross multiply

x = 11.9 * 52

x = 618.8                         grams

Now I have used an approximate mass for Chromium. The answer you get here is expected to reflect the weigth given on your periodic table Use that to get your answer. You should give a number very close to mine. Round to 3 places as in 619.

Method Two  Formula

mols = given mass / molecular mass

11.9 = given mass /  51.9961          Multiply both sides by  51.9961

11.9 *51.9961  = given mass            

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3 0
3 years ago
What is the total pressure (in atm) inside of a vessel containing N2 exerting a partial pressure of 0.256 atm, He exerting a par
Bezzdna [24]

Answer: Total pressure inside of a vessel is 0.908 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual partial pressures. exerted by each gas alone.

p_{total}=p_1+p_2+p_3

p_{N_2} = partial pressure of nitrogen = 0.256 atm

p_{He} = partial pressure of helium = 203 mm Hg = 0.267 atm  (760mmHg=1atm)

p_{H_2} = partial pressure of hydrogen =39.0 kPa = 0.385 atm  (1kPa=0.00987 atm)

Thus p_{total}=p_{H_2}+p_{He}+p_{H_2}

p_{total} =0.256atm+0.267atm+0.385atm =0.908atm

Thus total pressure (in atm) inside of a vessel is 0.908

8 0
3 years ago
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Answer:

B

Explanation:

7 0
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