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shusha [124]
3 years ago
11

Cual es la razón de que la molécula de oxigeno de calcio sea caO y no sea ca2O. o caO 2​

Chemistry
1 answer:
Fed [463]3 years ago
4 0

Answer:

In calcium oxide (CaO), oxygen and calcium are respectively a non-metal and a metal, whose bonding is based on the exchange of electrons to form an ionic bond, which balances their charges and makes it chemically stable.

Explanation:

<em>What is the reason that in the calcium oxide molecule is caO and not Ca₂O or CaO₂?</em>

Calcium is a metallic element -a soft metal- that is capable of bonding with a non-metallic element such as oxygen to form an ionic bond, so that each Ca atom will bond to a single O atom.

CaO (calcium oxide)

  • <em>Ca Z = 20  </em>
  • <em>O Z = 8</em>

          Ca              +         O       ---→       Ca⁺²    +      O ⁻²

     K   L   M   N               K   L                 K  L  M        K  L

     2   8    8   2               2   6                  2  8   8       2  8

The electron exchange that is observed occurs between +atom and atom, and for this reason the chemical formula of calcium oxide is CaO.

Calcium oxide (lime) is obtained by heating calcium carbonate (CaCO₃) to very high temperatures through the following reaction

                                CaCO₃ + heat → CaO + CO₂

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Name each of the following species for the following acid-base reactions. (The equilibrium lies to the right in each case, i.e.,
DaniilM [7]

Answer: a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

The species accepting a proton is considered as a base and after accepting a proton, it forms a conjugate acid.

The species losing a proton is considered as an acid and after loosing a proton, it forms a conjugate base

For the given chemical equation:

a) H_3O^++CH_3O^-\rightleftharpoons CH_3OH+H_2O

acid : hydronium ion

base : methoxide ion

conjugate acid : methanol

conjugate base: water

b) CH_3CH_2O^-+HCl\rightleftharpoons CH_3CH_2OH+Cl^-

acid : hydrogen chloride

base : ethoxide ion

conjugate acid : ethanol

conjugate base: chloride ion

c) NH_2^-+CH_3OH\rightleftharpoons NH_3+CH_3O^-

acid : methanol

base : amide ion

conjugate acid : ammonia

conjugate base: methoxide ion

.

3 0
2 years ago
If the density of a liquid 102g/cm^3, how many milligrams will be in 63 mL of that liquid?
Ede4ka [16]

Answer:

<h2>6426000 mg</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

63 mL = 63 cm³

We have

mass = 102 × 63 = 6426

But 1 g = 1000 mg

6426 g = 6426000 mg

We have the final answer as

<h3>6,426,000 mg</h3>

Hope this helps you

6 0
2 years ago
What is true about an element
stich3 [128]

Answer:

made from ine atom

Explanation:

one atom

5 0
2 years ago
When a nonmetal bonds with a nonmetal, they form a(n)
seropon [69]
Covalent bonds would be formed when a non-metal bonds with another non-metal 
6 0
3 years ago
How many moles of chlorine (Cl) atoms are in a sample of 1.72 × 1022 atoms? 0.0286 mol Cl 35.0 mol Cl 1.03 × 1023 mol Cl 1.04 ×
kogti [31]

Given information : Sample of 1.72\times 10^{22} atoms

We need to find the moles of Chlorine in the given sample.

We can say that we need to find moles from the given atoms.

Relation between mole and atom is given by : 1 mole = 6.022\times 10^{23} atoms

Where 6.022\times 10^{23} is Avogadro number.

1.72\times 10^{22} atoms\times \frac{1 mole}{6.022\times 10^{23} atoms}

1.72\times 10^{22}\times \frac{1 mole}{6.022\times 10^{23}}

On solving the above equation , atoms(unit) gets cancelled out and we get 0.0286 mol.

In the given sample the moles of Chlorine (Cl) is 0.0286 mol , so option A is correct.

6 0
3 years ago
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