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docker41 [41]
3 years ago
15

Valence electrons are the ONLY electrons that are involved in bonding.

Chemistry
1 answer:
ELEN [110]3 years ago
7 0

Yes that is definitely true

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The diagram below shows a gas sample being measured with an open-end mercury (Hg) manometer. If a barometer reads 730. 1 torr, w
IRISSAK [1]

The pressure of the gas in the flask (in atm) when Δh = 5.89 cm is 1.04 atm

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Atmospheric pressure (Pa) = 730.1 torr = 730.1 mmHg
  • Change in height (Δh) = 5.89 cm
  • Pressure due to Δh (PΔh) = 5.89 cmHg = 5.89 × 10 = 58.9 mmHg
  • Pressure of gas (P) =?

<h3>How to determine the pressure of the gas</h3>

The pressure of the gas can be obtained as illustrated below:

P = Pa + PΔh

P = 730.1 + 58.9

P = 789 mmHg

Divide by 760 to express in atm

P = 789 / 760

P = 1.04 atm

Thus, the pressure of the gas when Δh = 5.89 cm is 1.04 atm

Learn more about pressure:

brainly.com/question/22523697

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Missing part of question:

See attached photo

5 0
1 year ago
Which statement describes a difference between the humid continental and subarctic climates?
-BARSIC- [3]

Answer:

The humid continental climate has hot summers, while the subarctic climate has short, cool summers.

Explanation:

I did the lesson already and got it correct lol

6 0
3 years ago
How much heat energy is needed to heat 300g of water from 10 degrees Celsius to 50 degrees Celsius
elixir [45]

Answer:

There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C

Explanation:

<u>Step 1: </u>Data given

mass of water = 300 grams

initial temperature = 10°C

final temperature = 50°C

Temperature rise = 50 °C - 10 °C = 40 °C

Specific heat capacity of water = 4.184 J/g °C

<u>Step 2:</u> Calculate the heat

Q = m*c*ΔT

Q = 300 grams * 4.184 J/g °C * (50°C - 10 °C)

Q = 50208 Joule = 50.2 kJ

There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C

8 0
3 years ago
What is the correct order of coefficients to balance this equation?
11Alexandr11 [23.1K]

Answer:

2Al + 3CuSO4 → Al2(SO4)3 + 3Cu

Explanation:

I THINK

8 0
2 years ago
Determine the root-mean square speed of CO2 molecules that have an average kinetic energy of 4.2 x10-21 J per molecule.
strojnjashka [21]
<span>Determine the root-mean-square sped of CO2 molecules that have an average Kinetic Energy of 4.21x10^-21 J per molecule. Write your answer to 3 sig figs.
</span><span>
E = 1/2 m v^2 

If you substitute into this formula, you will get out the root-mean-square speed. 

If energy is Joules, the mass should be in kg, and the speed will be in m/s. 

1 mol of CO2 is 44.0 g, or 4.40 x 10^1 g or 4.40 x 10^-2 kg. 

If you divide this by Avagadro's constant, you will get the average mass of a CO2 molecule. 

4.40 x 10^-2 kg / 6.02 x 10^23 = 7.31 x 10^-26 kg 

So, if E = 1/2 mv^2 

</span>v^2 = 2E/m = 2 (4.21x10^-21 J)/7.31 x 10^-26 kg = 115184.68 
Take the square root of that, and you get the answer 339 m/s.
8 0
3 years ago
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