Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.
Solution : Given,
Mass of 
= 100 g
Molar mass of = 27 g/mole
Molar mass of 
= 28 g/mole
First we have to calculate moles of .
The given balanced chemical reaction is,
From the given reaction, we conclude that
2 moles of produced from 1 mole of
3.7 moles of produced from 
of
Now we have to calculate the mass of .
Mass of = Moles of × Molar mass of
Mass of = 1.85 mole × 28 g/mole = 51.8 g
Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.
MThe heat energy required to raise the temperature of 0.36Kg of copper from 22 c to 60 c is calculate using the following formula
MC delta T
m(mass)= 0.360kg in grams = 0.360 x1000 = 360 g
c(specific heat energy) = 0.0920 cal/g.c
delta T = 60- 23 = 37 c
heat energy is therefore= 360g x0.0920 cal/g.c x 37 c= 1225.44 cal
Answer:
When a front passes over an area, it means a change in the weather. Many fronts cause weather events such as rain, thunderstorms, gusty winds, and tornadoes. At a cold front, there may be dramatic thunderstorms. At a warm front, there may be low stratus clouds. Usually, the skies clear once the front has passed.
Explanation:
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Small peak at 3000large peak at 1685F: it contains two benzene rings that is connected by a bunch of carbons and ketone-Explanation: The spectrum shows a stretching absorption consistent with a ketone functional group: carbonyl C=O stretching at ~1685 cm-1. (An aldehyde, by contrast, would also show a ~2700 cm-1 absorption for the carbonyl C-H stretch.) The C=O stretching frequency is consistent with an aromatic ketone, such as in compound F (1,4-diphenyl-1,4-butanedione). In contrast, an aliphatic ketone absorbs at higher energy (~1710 cm-1). The spectrum also shows the typical ~1600 & ~1500 cm-1 absorptions of a phenyl group.
