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Gennadij [26K]
4 years ago
11

Consider the rection A b <--> C D. We will assume that both the forward and reverse reactions are elementary processes and

that the value of the euilibrium constant is very large
Chemistry
1 answer:
Tamiku [17]4 years ago
7 0

This is an incomplete question, here is a complete question.

Consider the reaction A+B ⇌ C+D. We will assume that both the forward and reverse reactions are elementary processes and that the value of the equilibrium constant is very large.

Which species predominate at equilibrium, reactants or products?

Answer  : The species predominate at equilibrium is, products.

Explanation:

Equilibrium reaction : It is a reaction which do not go on completion that means the reactant forms product and the products goes back to the reactants simultaneously.

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

In a chemical equilibrium reaction, the equilibrium state is achieved when the rate of forward reaction becomes equals to the rate of the backward reaction.

There are 3 conditions:

When K>1; the reaction is product favored.

When K; the reaction is reactant favored.

When K=1; the reaction is in equilibrium.

As, the value of equilibrium constant is very large that means K > 1. So, the reaction is product favored that means products are predominant.

Hence, the species predominate at equilibrium is, products.

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How many element are there on the periodic table?
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Over a long period of time, an igneous rock changes into a sedimentary rock. Which of these actions must have affected the igneo
Alla [95]

Answer: The actions that must have affected the igneous rock in order to form the sedimentary rock is that (It must have been broken down into sediments).

Explanation:

Rocks are solid structures that occurs naturally which is made up of different minerals. There are three main types of rocks, these includes:

--> METAMORPHIC ROCKS: These are the type of rocks which are formed by temperature and pressure changes inside the Earth.

--> SEDIMENTARY ROCKS: these rocks are usually formed from pre-existing rocks through the process of weathering (breaking down) of rocks.

--> IGNEOUS ROCKS: these rocks are formed when molten magma cools beneath or above the earth surface.

The actions that must have affected the igneous rock in order to form the sedimentary rock is that the igneous rocks are broken down into smaller pieces by erosion and weathering processes. Sediments which are formed accumulates at the earth surface. Over a long period of time, these sediments builds successive layers on top of one another. The sediments near the base hardens to form sedimentary rocks. This justifies the statement as a correct option (It must have been broken down into sediments).

3 0
3 years ago
A Silty Clay (CL) sample was extruded from a 6-inch long tube with a diameter of 2.83 inches and weighed 1.71 lbs. (a) Calculate
inna [77]

Answer:

a) the wet density of the CL sample is 0.0453 lb/in³

b) the water content in the sample is 65.37%

c) the dry density of the CL sample is 0.0274 lb/in³

Explanation:

Given that;

diameter d = 2.83 in

length L = 6 in

weight m = 1.71 lbs

A piece of clay sample had wet-weight of 140.9 grams  and dry-weight of 85.2 grams

a) wet density of the CL sample

wet density can be expressed as  p = M /v

V is volume of sample which is; π/4×d²×L

so p = M / π/4×d²×L

we substitute

p = 1.71 / (π/4 × (2.83)²× 6

p = 1.71 / 37.741

p = 0.0453 lbs/in³

so the wet density of the CL sample is 0.0453 lb/in³

b)

water content of sample is taken as;

w =  (wet_weight - dry_weight) / dry_weight

we substitute

w = (140.9 - 85.2) / 85.2

w = 55.7 / 85.2

w = 0.6537 = 65.37%

therefore the water content in the sample is 65.37%

c)

dry density of the CL sample

to determine the dry density, we say;

Sd = p / ( 1 + w )

we substitute

Sd = 0.0453 / ( 1 + 0.6537)

Sd = 0.0453 /  1.6537

Sd = 0.0274 lb/in³

therefore the dry density of the CL sample is 0.0274 lb/in³

8 0
3 years ago
A negatively charged balloon has 2.6 µc of charge. how many excess electrons are on this balloon? the elemental charge is 1.6 ×
Salsk061 [2.6K]
The given 2.6 µC of charge is due to a buildup of electrons, each of which has a charge of 1.6 x 10^-19 C. The 2.6 <span>µC is equivalent to 2.6 x 10^-6 C, so we can divide this by the individual charge of an electron:
</span>2.6 x 10^-6 C / 1.6 x 10^-19 (C/electron) = 1.625 x 10^13 electrons
5 0
4 years ago
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