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3 years ago

Which of the following is not true of atoms?

Chemistry

2 answers:

Alexandra [31]3 years ago

5 0

Answer:

they are composed of water

DiKsa [7]3 years ago

4 0

Answer:

guess its the last one should be right

Explanation:

prove me wrong

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Hello how do I solve data for plotting graphs?

OverLord2011 [107]

You could solve it by analyzing the points by graphing them on a coordinate plane

4 0

3 years ago

when you receive fluid in the hospital, it is often 0.9% saline solution. what would happen if the nurse used distilled water in

jasenka [17]

Answer:

The distilled water solution would be hypotonic to your blood cells, so they would gain water, swell, and possibly burst.

8 0

2 years ago

A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur

dsp73

Answer:

12.8 g of $O_{2}$ must be withdrawn from tank

Explanation:

Let's assume $O_{2}$ gas inside tank behaves ideally.

According to ideal gas equation- $PV=nRT$

where P is pressure of $O_{2}$ , V is volume of $O_{2}$ , n is number of moles of $O_{2}$ , R is gas constant and T is temperature in kelvin scale.

We can also write, $\frac{V}{RT}=\frac{n}{P}$

Here V, T and R are constants.

So, $\frac{n}{P}$ ratio will also be constant before and after removal of $O_{2}$ from tank

Hence, $\frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}$

Here, $\frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm}$ and $P_{after}=17atm$

So, $n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol$

So, moles of $O_{2}$ must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of $O_{2}$ = 32 g/mol

So, mass of $O_{2}$ must be withdrawn = $(32\times 0.40)g=12.8g$

7 0

2 years ago

What family has 4 valence electrons?

PilotLPTM [1.2K]

Answer:carbon group

Explanation:

4 0

2 years ago

How many joules of heat must be transferred to a 480-g aluminum pizza pan to raise its temperature from 22C to 234C? The specifi

NemiM [27]

The given formula for heat, Q=mc(Tf-Ti), is the best way to solve such problems with changes in temperature. It can be said that m is the mass of the substance. C is the specific heat of the substance. The term (Tf-Ti) is the change in temperature.

Q = mc(Tf-Ti) = 480g(0.96 J/g-C)(234-22) = 97689.6 Joules of heat

6 0

2 years ago