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3 years ago

Which of the following is correct oil viscosity for hybrid electric vehicle?

Engineering

1 answer:

sp2606 [1]3 years ago

5 0

SAE 0W-10 is the correct oil viscosity for hybrid electric vehicle.

Explanation:

The lubricant hydrodynamic friction which minimizes the viscosity grade and allows the fuel economy significantly.
The benefits are the cold oil and other conditions for temperature.
The grade of viscosity is very less and the oil improves the flow for the start up, the oil pressure fasts the delivery to build up, the raisings are fastly reversed and reached the fast temperature.
The requirement of hybrid electric vehicle also meets and there will be multiples of starts and stops of the gasoline engine during the different phases of hybrid vehicle.

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A 4-pole, 3-phase induction motor operates from a supply whose frequency is 60 Hz. calculate: 1- the speed at which the magnetic

DiKsa [7]

Answer:

The answer is below

Explanation:

1) The synchronous speed of an induction motor is the speed of the magnetic field of the stator. It is given by:

$n_s=\frac{120f_s}{p}\\ Where\ p\ is \ the \ number\ of\ machine\ pole, f_s\ is\ the\ supply \ frequency\\and\ n_s\ is \ the \ synchronous\ speed(speed \ of\ stator\ magnetic \ field)\\Given: f_s=60\ Hz, p=4. Therefore\\\\n_s=\frac{120*60}{4}=1800\ rpm$

2) The speed of the rotor is the motor speed. The slip is given by:

$Slip=\frac{n_s-n_m}{n_s}. \\ n_m\ is\ the \ motor\ speed(rotor\ speed)\\Slip = 0.05, n_s= 1800\ rpm\\ \\0.05=\frac{1800-n_m}{1800}\\\\ 1800-n_m=90\\\\n_m=1800-90=1710\ rpm$

3) The frequency of the rotor is given as:

$f_r=slip*f_s\\f_r=0.04*60=2.4\ Hz$

4) At standstill, the speed of the motor is 0, therefore the slip is 1.

The frequency of the rotor is given as:

$f_r=slip*f_s\\f_r=1*60=60\ Hz$

6 0

3 years ago

tech A says that a Hall-effect sensor can be used in an electronic ignition system. Tech B says that an optical-type sensor can

Alex

Answer:

Both Tech A and Tech B are correct.

Explanation:

The Hall effect sen sensor are used to control displacements and rotations of various body components of the vehicles, engine vibrations , and the ignition system

The optical-type sensor converts rays of light into electronic signals. It measures the quantity physically of which the translates to a form that is understandable or readable by an instrument. An optical sensor is larger part of a system that integrates light sources, a device for measuring and the optical sensor, which therefore is usually connected to an electrical trigger.

6 0

3 years ago

Why is flexibility the most obvious benefit of road transportation select all that apply

ser-zykov [4K]

What am I going to select?? What are my choices bro????

7 0

3 years ago

A bridge hand consists of 13 cards. One way to evaluate a hand is to calculate the total high point count (HPC) where an ace is

son4ous [18]

Answer: Let us use the pickled file - DeckOfCardsList.dat.

Explanation: So that our possible outcome becomes

7♥, A♦, Q♠, 4♣, 8♠, 8♥, K♠, 2♦, 10♦, 9♦, K♥, Q♦, Q♣

HPC (High Point Count) = 16

4 0

3 years ago

An insulated piston-cylinder device contains 0.15 of saturated refrigerant-134a vapor at 0.8 MPa pressure. The refrigerant is no

Stells [14]

Answer:

Assumption:

1. The kinetic and potential energy changes are negligible

2. The cylinder is well insulated and thus heat transfer is negligible.

3. The thermal energy stored in the cylinder itself is negligible.

4. The process is stated to be reversible

Analysis:

a. This is reversible adiabatic(i.e isentropic) process and thus $s_{1} =s_{2}$

From the refrigerant table A11-A13

$P_{1} =0.8MPa$ $\left \{ {{ {{v_{1}=v_{g} @0.8MPa =0.025645 m^{3/}/kg } } \atop { {{u_{1}=u_{g} @0.8MPa =246.82 kJ/kg } - also {{s_{1}=s_{g} @0.8MPa =0.91853 kJ/kgK } } \right.$

sat vapor

m= $\frac{V}{v_{1} } =\frac{0.15}{0.025645} =5.8491 kg\\and \\\\P_{2} =0.2MPa \left \{ {{x_{2} =\frac{s_{2} -s_{f} }{s_{fg }}=\frac{0.91853-0.15449}{0.78339} = 0.9753 \atop {u_{2} =u_{f} +x_{2} }(u_{fg}) = 38.26+0.9753(186.25)= 38.26+181.65 =219.9kJ/kg \right. \\s_{1} = s_{2}$