Answer:
i) SF:
ii) BM : 
Explanation:
Let's take,
Making y the subject of formula, we have :

For shear force (SF), we have:
This is the area of the diagram.

The shear force equation =
For bending moment (BM):


The bending moment equation =

Answer:
A civil engineer.
Explanation:
Civil engineering is the science that deals with the design, creation and maintenance of constructions for civil use on the earth's surface. Thus, this specialty seeks to adapt soils to the needs of life in society, creating buildings, bridges, and all other constructions adapted to civil life, while taking care of the correct use of soils and the correct distribution of spaces and resources. to be used for such constructions.
The back-work ratio much higher in the Brayton cycle than in the Rankine cycle because a gas cycle is the Brayton cycle, while a steam cycle is the Rankine cycle. Particularly, the creation of water droplets will be a constraint on the steam turbine's efficiency. Since gas has a bigger specific volume than steam, the compressor will have to work harder while using gas.
<h3>What are modern Brayton engines?</h3>
Even originally Brayton exclusively produced piston engines, modern Brayton engines are virtually invariably of the turbine variety. Brayton engines are also gas turbines.
<h3>What is the ranking cycle?</h3>
A gas cycle is the Brayton cycle, while the Ranking cycle is a steam cycle. The production of water droplets will especially decrease the steam turbine's performance. Gas-powered compressors will have to do more work since gas's specific volume is greater than steam's.
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Answer:
The exit temperature is 293.74 K.
Explanation:
Given that
At inlet condition(1)
P =80 KPa
V=150 m/s
T=10 C
Exit area is 5 times the inlet area
Now

If consider that density of air is not changing from inlet to exit then by using continuity equation

So 
m/s
Now from first law for open system

Here Q=0 and w=0

When air is treating as ideal gas

Noe by putting the values



So the exit temperature is 293.74 K.
Answer:
Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22
Explanation:
Assuming a = 2b
Attached below is the required steps to the solution
The cutoff frequencies for the first ten modes of a rectangular waveguide listed in ascending order is :
Fcte10 < Fcte01 = Fcte0 < Fctm11 < Fcte21 = Fctm21 < Fcte12 = Fctm12 < Fcte22