1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jekas [21]
2 years ago
14

Suppose that you are standing on a train accelerating at 0.39g. What minimum coefficient of static friction must exist between y

our feet and the floor if you are not to slide?
Static friction is the friction that exist between a stationary object and the surface on which it is resting. Coefficient of friction tells us how strongly the two surfaces grip each other. Static friction and coefficient of friction are related to each other by the relation;

Fs=μsN

where,

Fs=Force of static friction
μs=Coefficient of friction
N=Normal force
Physics
1 answer:
timurjin [86]2 years ago
5 0

Answer:

0.39

Explanation:

In order not to slide, you must have exactly the same acceleration of the train:

a=0.39 g

where

g = 9.81 m/s^2

There is only one force acting on you: the static frictional force that "pulls" you forward, and it is given by

F_s = \mu_s mg

According to Newton's second law, the net force acting on you (so, the frictional force) must be equal to your mass times the acceleration, so we have

F= ma = \mu_s mg

from which we find

\mu_s = \frac{a}{g}=\frac{0.39 g}{g}=0.39

so, the minimum coefficient of static friction must be 0.39.

You might be interested in
How long does it take to drive from one end of california to the other?
evablogger [386]

California is the third largest state and the only two bigger states than California are Alaska and Texas so it really depends on how you want to cross it. There are two routes to cross California depending on how you plan your visit and places you need to see. Depending on the route you take crossing California can take from twelve to almost sixteen hours of drive. 

8 0
3 years ago
Investigators are researching the appearance of a strange movement of objects in what the local community considers a haunted ho
wolverine [178]

Answer:

0.18216 T

Explanation:

N = Number of turns = 219

A = Area = \pi r^2

r = Radius = 1 cm

\omega = Angular speed = 40\times 2\pi

Maximum emf is given by

\epsilon=NBA\omega\\\Rightarrow B=\dfrac{\epsilon}{NA\omega}\\\Rightarrow B=\dfrac{3.15}{219\times \pi 0.01^2\times 40\times 2\pi}\\\Rightarrow B=0.18216\ T

The strength of the magnetic field is 0.18216 T

8 0
2 years ago
A boat of mass 225 kg drifts along a river at a speed of 21 m/s to the west. what impulse is required to decrease the speed of t
zzz [600]
The impulse required to decrease the speed of the boat is equal to the variation of momentum of the boat:
J=\Delta p=m \Delta v
where
m=225 kg is the mass of the boat
\Delta v=v_f-v_i=15 m/s-21 m/s=-6 m/s is the variation of velocity of the boat
By substituting the numbers into the first equation, we find the impulse:
J=m\Delta v=(225 kg)(-6 m/s)=-1350 N s
and the negative sign means the direction of the impulse is against the direction of motion of the boat.
8 0
3 years ago
Read 2 more answers
If you dribble a basketball with a frequency of 1.77 Hz, how long does it take for you to complete 12 dribbles?
Licemer1 [7]
<h2>It takes 6.78 seconds to complete 12 dribbles.</h2>

Explanation:

Frequency of dribble = 1.77 Hz

That is

         Number of dribbles in 1 second = 1.77

         \texttt{Time taken for 1 dribble = }\frac{1}{1.77}=0.565s

Now we need to find how long does it take for you to complete 12 dribbles.

         Time taken for 12 dribbles = 12 x Time taken for 1 dribble

         Time taken for 12 dribbles = 12 x 0.565

         Time taken for 12 dribbles = 6.78 seconds      

It takes 6.78 seconds to complete 12 dribbles.  

8 0
2 years ago
A 45.2-kg person is on a barrel ride at an amusement park. She stands on a platform with her back to the barrel wall. The 3.74-m
elena-14-01-66 [18.8K]

Answer:

  • <u><em>1,230N</em></u>

Explanation:

<u>1. Name of the variables:</u>

   f:frequency\\\\ \omega:angular\text{ }speed\\\\ a_c:centripetal\text{ }acceleration\\\\ F_c:centripetal\text{ }force\\ \\ m:mass\\ \\ d:diameter\\ \\ r:radius\\ \\ g:gravitational\text{ }acceleration

<u>2. Formulae:</u>

         f=\dfrac{number\text{ }of\text{ }revolutions}{time}

          \omega=2\pi f

          a_c=\omega^2 r

           F_c=m\times a_c

<u>3. Solution (calculations)</u>

       f=\dfrac{1}{1.65s}=0.\overline{60}s^{-1}

       \omega=2\pi\times0.\overline{60}\approx 3.808rad/s

      a_c=(3.808rad/s)^2\times (3.74/2m)=27.12m/s^2

      F_c=45.2kg\times27.12m/s^2=1,225.67N\approx 1,230N

3 0
3 years ago
Other questions:
  • An electric air heater consists of a horizontal array of thin metal strips that are each 10 mm long in the direction of an airst
    9·1 answer
  • A person watches an ambulance drive by them while emitting a steady sound from its siren. When the ambulance passes the person (
    12·1 answer
  • Plzzzzzzz help me quick
    11·1 answer
  • What is the difference between relative time and absolute time?
    12·1 answer
  • Highlight two factors which show that heat from the sun does reach the earth surface by conversation
    14·1 answer
  • What is the displacement of the object from 12 seconds to 16 seconds
    15·1 answer
  • A golf ball is hit with an initial velocity of 20m/s at an angle of 30° to the horizontal. calculate;
    5·1 answer
  • What is the medium through which sound travels inside a bird’s body? (HINT: three-letter word)
    13·1 answer
  • A simulation shows whether changing various weather conditions increases
    6·1 answer
  • If the car is traveling at a velocity of 15 m/s, what is the approximate centripetal acceleration of the car?.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!