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aliya0001 [1]
3 years ago
7

Remember this quote?!

Chemistry
1 answer:
muminat3 years ago
8 0

Answer:

Yes

Explanation:

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Which is one way that topographic maps are different from other maps?
anzhelika [568]
One way they are different is that they show elevation
5 0
3 years ago
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Magnesium burns with a very bright light. When the flame goes out, a White powder is left behind. what is the word equation for
melisa1 [442]
When magnesium is burned, it reacts with oxygen in air not with the fire. The fire is the energy needed for the reaction to happen. Magnesium reacts with oxygen forming magnesium oxide. The light emitted from the reaction is because the reaction produced a lot of heat.
6 0
3 years ago
What is the mass of 3.77mol of K3N?
AleksAgata [21]
<h3>Answer:</h3>

495 g K₃N

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.77 mol K₃N

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of K₃N - 3(39.10) + 14.01 = 131.31 g/mol

<u>Step 3: Convert</u>

  1. Set up:                       \displaystyle 3.77 \ mol \ K_3N(\frac{131.31 \ g \ K_3N}{1 \ mol \ K_3N})
  2. Multiply/Divide:         \displaystyle 495.039 \ g \ K_3N

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

495.039 g K₃N ≈ 495 g K₃N

5 0
3 years ago
What is the oxidation number of chlorine in HClO4?
Elza [17]

CIO4-=-1

CI=4O=-1

O has a 2- oxidation change so

CI+4(-2)=-1

CI+(-8)=-1

CI=-1+8=7

So the oxidation number of chlorine is 7 in this case

8 0
3 years ago
A sample of 0.53 g of carbon dioxide was obtained by heating 1.31 g of calcium carbonate. what is the percent yield for this rea
Masja [62]

CaCO3(s) ⟶ CaO(s)+CO2(s) 

<span>
moles CaCO3: 1.31 g/100 g/mole CaCO3= 0.0131 </span>

<span>
From stoichiometry, 1 mole of CO2 is formed per 1 mole CaCO3, therefore 0.0131 moles CO2 should also be formed. 
0.0131 moles CO2 x 44 g/mole CO2 = 0.576 g CO2 </span>

Therefore:<span>
<span>% Yield: 0.53/.576 x100= 92 percent yield</span></span>

4 0
3 years ago
Read 2 more answers
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