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Mkey [24]
3 years ago
12

What type of noise is most difficult to remove from a digital signal? why?

Physics
1 answer:
Lilit [14]3 years ago
8 0
Interference if the hardest to remove due to the superposition of the frequencies of the radio waves
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Which elements are found in all four components of Earth?​
kifflom [539]

Answer:

oxygen silicon aluminun iron

3 0
3 years ago
A 400 N steel ball is suspended by a light rope from<br>the ceiling. The tension in the rope is​
alina1380 [7]

Answer:

As force = tension in string so tension in string is 400N

Explanation:

8 0
3 years ago
What is the speed of a cyclist that rides west 88 km in 32 minutes?
suter [353]

Answer:

The speed of the cyclist is 2.75 km/min.

Explanation:

Given

  • The distance d = 88 km
  • Time t = 32 minutes

To determine

We need to find the speed of a cyclist.

In order to determine the speed of a cyclist, all we need to do is to divide the distance covered by a cyclist by the time taken to cover the distance.

Using the formula involving speed, time, and distance

s=\frac{d}{t}

where

  • s = speed
  • d = distance covered
  • t = time taken

substitute d = 88, and t = 32 in the formula

s=\frac{d}{t}

s=\frac{88}{32}

Cancel the common factor 8

s=\frac{11}{4}

s=2.75 km/min

Therefore, the speed of the cyclist is 2.75 km/min.

8 0
3 years ago
Why echo sound cannot be heard in small room
Art [367]
They can't hear an echo in small room because in it the sound can't be reflected back. For an echo of a sound to be heard,the minimum distance between the source of sound and the walls of the roomshould be 17.2 m. Obviously,in asmall room echoes cannot beheard.
7 0
3 years ago
A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below. A coordinate plane has a hor
Leno4ka [110]

Answer:

Explanation:

An impulse results in a change of momentum.

The impulse is the product of a force and a distance. This will be represented by the area under the curve

a) W = ½(4.00)(3.00) = 6.00 J

b) W = (11.0 - 4.00)(3.00) = 21.0 J

c) W = ½(17.0 - 11.0)(3.00) = 9.00 J

d) ASSUMING the speed at x = 0 is in the direction of applied force

½(3.00)(v₄²) = ½(3.00)(0.450²) + 6.00

v₄ = 2.05 m/s

½(3.00)(v₁₇²) = ½(3.00)(0.450²) + 6.00 + 21.0 + 9.00

v₁₇ = 4.92 m/s

If the initial speed is NOT in the direction of applied force, the final speed will be slightly less in both cases.

7 0
3 years ago
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