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Anna007 [38]
3 years ago
12

A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of

29.5 m. The runner starts the race at a constant speed. If she completes the 200-m dash in 24.4 s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track
Physics
1 answer:
Leto [7]3 years ago
5 0

Answer: 2.27\ m/s^2

Explanation:

Given

Length of the race track L=200\ m

the radius of curvature of the track r=29.5\ m

time taken to run on track is t=24.4\ s

Speed of runner is

\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s

Centripetal acceleration is

\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2

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Answer:

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Explanation:

To find the thermal energy gained by the ice you use the following formula:

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**URGENT PLEASE HELP**
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Answer:

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<em>hope it helps:)</em>

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