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Snezhnost [94]
3 years ago
7

A mixture of gaseous reactants is put into a cylinder, where a chemical reaction turns them into gaseous products. The cylinder

has a piston that moves in or out, as necessary, to keep a constant pressure on the mixture of 1atm. The cylinder is also submerged in a large insulated water bath. (See sketch at right.) From previous experiments, this chemical reaction is known to release 223.kJ of energy. The temperature of the water bath is monitored, and it is determined from this data that 173.kJ of heat flows out of the system during the reaction.
Does the temperature of the water bath go up or down?
Does the piston move in or out?
Does heat flow into or out of the gaseous mixture?
How much heat flows?
Show transcribed image text
Chemistry
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

The answers to the questions are as follows

  1. The temperature of the water bath goes up
  2. The piston moves out
  3. Heat flows out of the gaseous mixture
  4. 173.kJ flows out of the system

Explanation:

  • From the question, it is noted that 173.kJ of heat flows out of the system into the insulated water bath therefore the temperature of the water bath goes up

as seen in the relation ΔH = m·c·ΔT

Where ΔH heat measured by temperature  rise ΔT of a given mass of water m of specific heat capacity of 4.2 J/g°C

  • The amount of heat measured from previous experiment is more than the heat from the present reaction therefore since in the present reaction is constant pressure and from the first law of thermodynamics Energy can neither be created nor destroyed, the balance heat will be transformed to work evidence in the piston moving out

ΣH = Q + W  where

w = P × ΔV = P × (P₂ - P₂)

  • Heat flows out of the gaseous mixture and is sensed from the rise in the temperature of the water bath
  • 173.kJ flows out of the system

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Examples of a pure substances
DiKsa [7]

Answer:

Explanation:

Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements.

3 0
2 years ago
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200.0 mL of 3.85 M HCl is added to 100.0 mL of 4.6 M barium hydroxide. The reaction goes to completion. What is the concentratio
Ede4ka [16]

Answer:

2.387 mol/L

Explanation:

The reaction that takes place is:

  • 2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

First we <u>calculate how many moles of each reagent were added</u>:

  • HCl ⇒ 200.0 mL * 3.85 M = 203.85 mmol HCl
  • Ba(OH)₂ ⇒ 100.0 mL * 4.6 M = 460 mmol Ba(OH)₂

460 mmol of Ba(OH)₂ would react completely with (2*460) 920 mmol of HCl. There are not as many mmoles of HCl so Ba(OH)₂ will remain in excess.

Now we <u>calculate how many moles of Ba(OH)₂ reacted</u>, by c<em>onverting the total number of HCl moles to Ba(OH)₂ moles</em>:

  • 203.85 mmol HCl * \frac{1mmolBa(OH)_{2}}{2mmolHCl}= 101.925 mmol Ba(OH)₂

This means the remaining Ba(OH)₂ is:

  • 460 mmol - 101.925 mmol = 358.075 mmoles Ba(OH)₂

There are two OH⁻ moles per Ba(OH)₂ mol:

  • OH⁻ moles = 2 * 358.075 = 716.15 mmol OH⁻

Finally we <u>divide the number of OH⁻ moles by the </u><u><em>total</em></u><u> volume</u> (100 mL + 200 mL):

  • 716.15 mmol OH⁻ / 300.0 mL = 2.387 M

So the answer is 2.387 mol/L

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3 years ago
What is the difference between the endpoint and the equivalence point?
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Endpoint . this is when the color of the indicator changes  while  equivalence is when added titrant is chemically equivalent completely to the analyte sample  

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3 years ago
What is the mass of 4.67 mol of Sulfuric Acid (H2SO4)
Ivahew [28]
<h3>Answer:</h3>

458 g H₂SO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

4.67 mol H₂SO₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of S - 32.07 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 4.67 \ mol \ H_2SO_4(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4})
  2. Multiply/Divide:                \displaystyle 458.08 \ g \ H_2SO_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

458.08 g H₂SO₄ ≈ 458 g H₂SO₄

6 0
2 years ago
The combustion of caffeine with the molecular masses is given below. If you have 0.150 grams of caffeine, how much NO2 in grams
lord [1]

Answer:

1. 0.14 g of NO2.

2. 0.27 g of CO2.

Explanation:

The balanced equation for the reaction is given below:

2C8H10N4O2 + 27O2 —> 16CO2 + 10H2O + 8NO2

Next, we shall determine the mass of caffeine, C8H10N4O2 that reacted and the masses of nitrogen (iv) oxide, NO2 and carbon (iv) oxide, CO2 produced from the balanced equation. This can be obtained as follow:

Molar mass of of C8H10N4O2 = 194.19 g/mol

Mass of C8H10N4O2 from the balanced equation = 2 × 194.19 = 388.38 g

Molar mass of CO2 = 44.01 g/mol

Mass of CO2 from the balanced equation = 16 × 44.01 = 704.16 g

Molar mass of NO2 = 46.01 g/mol

Mass of NO2 from the balanced equation = 8 × 46.01 = 368.08 g

Summary:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2 and 368.08 g of NO2.

1. Determination of the mass of NO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 368.08 g of NO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 368.08) / 388.38 = 0.14 g of NO2.

Therefore, 0.14 g of NO2 was obtained from the reaction.

2. Determination of the mass of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

388.38 g of caffeine, C8H10N4O2 reacted to produce 704.16 g of CO2.

Therefore, 0.15 g of caffeine, C8H10N4O2, will react to produce = (0.15 × 704.16) / 388.38 = 0.27 g of CO2.

Therefore, 0.27 g of CO2 was obtained from the reaction.

8 0
2 years ago
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