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LiRa [457]
3 years ago
13

What type of chemical reaction is so3(g) + h2o(l) → h2so4(aq)?

Chemistry
1 answer:
Sloan [31]3 years ago
3 0
Note: Above question is incomplete. Complete question is
<span>What type of chemical reaction is so3(g) + h2o(l) → h2so4(aq)
a) Neutralization
b) Decomposition
c) Combination
d) Single displacement reaction
...............................................................................................................
Solution:
In current context, following things may be noted
1) Neutralization reactions: In neutralization reactions, acid and base combine to form salt and water.
b) Decomposition reaction: R</span><span>eaction in which a single substance broken down two or more smaller substances is refereed as decomposition reaction. Decomposition reactions are characterized be present of single molecule on reactant side. 
c) Combination reaction: In a recombination reaction</span><span> two or more molecules combine to form a single product.
d) Single displacement reaction: R</span><span>eaction in which an element within a compound is displaced by a another element is referred as single displacement reaction. 

Above reaction satisfies the criteria of combination reaction, hence correct answer is option C, combination. </span>
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Non metals whose 2 forms<br> 1]very hard <br> 2] conductor of electricity
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Answer:

Diamond

Explanation:

Diamond has covalent bonds, which makes it a non-metal.

However, it also has a tetrahedral structure, which holds its C atoms together by strong forces, thus making it hard.

Diamond also has free-moving electrons due to its tetrahedral structure, thus making it possible to conduct electricity.

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3 years ago
A student balances the following redox reaction using half-reactions.
ICE Princess25 [194]
Answer: 6.

Explanation:

1) Aluminum

Al^0-3e^----\ \textgreater \ Al^{3+}

So each atom of aluminum lost 3 electrons to pass from 0 oxidation state to 3+ oxidation state.

2) Manganesium

Mn^{2+}+2e^{-}---\ \textgreater \ Mn

So, each ion of Mn(2+) gained 2 electrons pass from 2+ oxidation state to 0.

3) Balance

Multiply aluminum half-reaction (oxidation) by 2 and multiply manganesium half-raction (reduction) by 3:

2Al^{0}-6e^{-}---\ \textgreater \ 2Al^{3+}&#10;&#10;3Mn^{2+}+6e^{-}---\ \textgreater \ 3Mn^{0}

4) Net equation

Add the two half-equations:

2Al^{0}+3Mn^{2+}----\ \textgreater \ 2Al^{3+}+3Mn^{0}

As you see the left side has 2 Al, 3Mn, and 3*2 positive charges.

The right side has 2 Al, 3 Mn, and 2*3 positive charges.

So, the equation is balanced.

5) Count the number of electrons involved.

As you see 2 atoms of aluminum lost 6 electrons (3 each).

That is the answer to the question. 6 electrons will be lost.
5 0
3 years ago
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Explanation:

May I have brainliest please? :)

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I hope this helps/answers your question! I vaguely remember getting this question before too
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