Two charges, q1 and q2, are separated by a certain distance r. if the magnitudes of the charges are halved and their separation
1 answer:
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Answer:
Acceleration, in m/s, of such a rock fragment =
Explanation:
According to Newton's Third Equation of motion
Where:
is the final velocity
is the initial velocity
a is the acceleration
s is the distance
In our case:
So Equation will become:
Acceleration, in m/s, of such a rock fragment =
Answer:
The time taken by the projectile to hit the ground is 6.85 sec.
Explanation:
Given that,
Vertical height of cliff = 230 m
Distance = 300 m
Suppose, determine the time taken by the projectile to hit the ground.
We need to calculate the time
Using second equation of motion
Where, s = vertical height of cliff
u = initial vertical velocity
g = acceleration due to gravity
Put the value in the equation
Hence, The time taken by the projectile to hit the ground is 6.85 sec.