Answer:
8.75 g of ZnO
Solution:
The Balance Chemical Reaction is as follow,
2 ZnS + 3 O₂ → 2 ZnO + 2 SO₂
Step 1: Find out the limiting reagent as;
According to Equation ,
194.94 g (2 mole) ZnS reacts with = 96 g (3 moles) of O₂
So,
12.85 g of ZnS will react with = X g of O₂
Solving for X,
X = (12.85 g × 96 g) ÷ 194.94 g
X = 6.32 g of O₂
It means for total utilization of 12.85 g of ZnS we require 6.32 g of O₂, but we are provided with 15.91 g of O₂. Therefore, ZnS is the limiting reagent and will control the yield.
Step 2: Calculate Amount of ZnO produced as;
According to Equation ,
194.94 g (2 mole) ZnS produces = 132.81 g (2 moles) of ZnO
So,
12.85 g of ZnS will produce = X g of ZnO
Solving for X,
X = (12.85 g × 132.81 g) ÷ 194.94 g
X = 8.75 g of ZnO
Answer:
0.057 M
Explanation:
Step 1: Given data
Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴
Concentration of mercury (II) ion: 0.085 M
Step 2: Write the reaction for the solution of HgBr₂
HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻
Step 3: Calculate the bromide concentration needed for a precipitate to occur
The Ksp is:
Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²
[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M
I would say that the answer is A. A pot of soup is 50 grams of salt per liter because B. has a lower gram of salt per liter and in C if you divide 360 by 10 you would get 36 grams of salt per liter
The heat transfer to thermal energy to the ice cube causes its molecules to move faster.
Hope this helped! :)