Question

15 POINTS

Answer 1

Answer:

Acceleration of the bullet while moving into the clay is -312500 ms⁻²

Explanation:

Given data

Initial velocity (v₁) = 250 m/s                 Final velocity (v₂) = 0 m/s

Distance (s)= 0.1 m                            acceleration (a) = ?

Using 3rd equation of motion

                  2as = v₂²- v₁²

       2 × a × 0.1 = 0² - 250²

            0.2 × a = -62500

                      a = -62500/0.2

                     a = -312500 m/s²

Here negative sign indicate that bullet slow down and it is deceleration i.e negative acceleration.