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3 years ago

11

How many electrons do alkali metals have in their outer shell?

2 answers:

DIA [1.3K]3 years ago

6 0

These metals have only one electron<span> in their outer shell. Therefore, they are ready to lose that </span>one electron<span> in ionic bonding with other elements. #stay smoking

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BARSIC [14]3 years ago

3 0

The outer shell can hold 1 electron

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What is denser medium?

abruzzese [7]

Answer: A medium in which speed of light is more is known as optically rarer medium and a medium in which speed of light is less is said to be optically denser medium. For example in air and water, air is raer and water is a denser medium.

Explanation:

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3 years ago

A book is sitting on a desk. What best describes the normal force acting on the book?

hjlf

Answer:

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3 years ago

Replacing an object attached to a spring with an object having 14 the original mass will change the frequency of oscillation of

Pachacha [2.7K]

Answer:

<em>The frequency changes by a factor of 0.27.</em>

<em></em>

Explanation:

The frequency of an object with mass m attached to a spring is given as

$f$ = $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

where $f$ is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

$f_{n}$ = $\frac{1}{2\pi } \sqrt{\frac{k}{14m} }$

simplifying, we have

$f_{n}$ = $\frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }$

$f_{n}$ = $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$

if we divide this final frequency by the original frequency, we'll have

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ ÷ $\frac{1}{2\pi } \sqrt{\frac{k}{m} }$

==> $\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }$ x $2\pi \sqrt{\frac{m}{k} }$

==> 1/3.742 = <em>0.27</em>

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3 years ago

5. A body travels in a circle at a constant speed, it

nata0808 [166]

A the same acceleration

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3 years ago

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Solve for A if F=MA and F=100 and M=25?

inn [45]

Answer:

<h3> $\boxed{ \boxed{ \bold{A = 4}}}$ </h3>

Explanation:

Given,

F = 100 , M = 25

Now, let's find the value of A

$\sf{F = MA}$

plug the values

⇒ $\sf{100 = 25 A}$

Swap the sides of the equation

⇒ $\sf{25A = 100}$

Divide both sides of the equation by 25

⇒ $\sf{ \frac{25A}{25} = \frac{100}{25} }$

Calculate

⇒ $\sf{A = 4}$

Hope I helped!

Best regards!!

5 0

3 years ago

Read 2 more answers