Answer:
51793 bright-dark-bright fringe shifts are observed when the mirror M2 moves through 1.7cm
Explanation:
The number of maxima appearing when the mirror M moves through distance \Delta L is given as follows,
Here,
= is the distance moved by the mirror M
is the wavelenght of the light used.
= 0.017m
Therefore, 51793 bright-dark-bright fringe shifts are observed when the mirror M2 moves through 1.7
Answer:
20.7 s
Explanation:
The equation to calculate the velocity for a uniform acceleration a, time t and initial velocity v₀:
v = a*t + v₀
Solve for t:
t = (v - v₀)/a
-- Bob covered a distance of (32m + 45m) = 77 meters.
-- His displacement is the straight-line distance and direction
from his starting point to his ending point.
The straight-line distance is
D = √(32² + 45²)
D = √(1,024 + 2,025)
D = √3,049 = 55.22 meters
The direction is the angle whose tangent is (32/45) south of east.
tan⁻¹(32/45) = tan⁻¹(0.7111...) = 35.42° south of east.
Answer:
C. Both technicians A and B
Explanation:
Both technicians are absolutely correct because a functional test light is meant to light on both test point if the fuse is working fine which implies that, if the test light doesn't light on both sides then there must be a fault with the fuse. So, both technicians A and B are very correct.
Mesophyll only occurs in some plants, and not the usual C3 plants that everyone learns about. In fact, mesophyll is mainly used in photosynthesis - for its light dependent reactions (primary reactions). Therefore, I'd say it's c) the structure which stores glucose for later use.
