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sweet-ann [11.9K]
3 years ago
14

Help me pleaseeeeeeddd​

Physics
1 answer:
Vladimir79 [104]3 years ago
7 0

Answer:

Explanation:

a )

According to graph the object moves with constant velocity of 10 m /s during first 8 s and then its velocity changes to - 5 m /s from 8 th second upto 12 th second .

Initial displacement = 8 m

displacement during 8 s = velocity x time

= 8 x 10 = 80 m

total displacement = 88 m

b )

displacement during period from 8 th to 12 th s

= - 5 x 4 = - 20 m

total displacement after 12 s

= 88 - 20 = 68 m

c ) average speed = total distance covered during 12 s / total time

= (80 + 20) / 12

= 8.33 m /s

average velocity = total displacement during 12 s  / total time

= 80 - 20 / 12  

= 60 / 12

= 5 m /s .

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makkiz [27]

Answer:

the answer is D

Explanation:

if you read the paragraph and question number 4 it tells you the answer wich is d

3 0
3 years ago
Winnie the Pooh pushes a jug of with a force of 60 Newtons 3.5 meters. How much work did he do?
KonstantinChe [14]

Answer:

For him being such a fat bear, it would have taken alot of work

Explanation:

7 0
3 years ago
Two balls have their centers 2.0 m apart. One ball has a mass of m1 = 7.9 kg. The other has a mass of m2 = 6.1 kg. What is the g
maks197457 [2]

Answer:

3.036×10⁻¹⁰ N

Explanation:

From newton's law of universal gravitation,

F = Gm1m2/r² .............................. Equation 1

Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.

G = gravitational constant

Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²

Substituting into equation 1

F = 6.67×10⁻¹¹×7.9×6.1/2²

F = 321.427×10⁻¹¹/4

F = 30.36×10⁻¹¹

F = 3.036×10⁻¹⁰ N

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8 0
4 years ago
1. A jet lands on an aircraft carrier at a speed of 140 mi/h [ 1.00 mile = 1.61 km]
Iteru [2.4K]
Answer:

Acceleration, a = -31.29 m/s²

Explanation:

It is given that, Initial speed of the aircraft, u = 140 mi/h =

62.58 m/s

Finally, it stops, v = 0

Time taken, t = 2 s

Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :

a = t

0-62.58 2 a =

a = -31.29 m/s²

So, the acceleration of the aircraft is 31.29 m/s²

and the car is decelerating. Hence, this is the required solution.
(i found this answer becuase i could do the math)

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3 years ago
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