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3 years ago

The weight of an apple at 4r from earth is of that on earth

2 answers:

4 0

W = m.g = weight
g = Gme/Re**2 where G= universal gravitational constant , Re= radius of the earth
me= mass of the earth
therefore it weighs 16 times less

Virty [35]3 years ago

4 0

1/16 of the earths mass

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A bug is 12 cm from the center of a turntable that is rotating with a frequency of 45 rev/min . What minimum coefficient frictio

Agata [3.3K]

Answer:

The minimum coefficient of friction is 0.27.

Explanation:

To solve this problem, start with identifying the forces at play here. First, the bug staying on the rotating turntable will be subject to the centripetal force constantly acting toward the center of the turntable (in absence of which the bug would leave the turntable in a straight line). Second, there is the force of friction due to which the bug can stick to the table. The friction force acts as an intermediary to enable the centripetal acceleration to happen.

Centripetal force is written as

$F_c = m\frac{v^2}{r}$

with v the linear velocity and r the radius of the turntable. We are not given v, but we can write it as

$v = r\omega$

with ω denoting the angular velocity, which we are given. With that, the above becomes:

$F_c = m\frac{v^2}{r}=m\omega^2 r$

Now, the friction force must be at least as much (in magnitude) as Fc. The coefficient (static) of friction μ must be large enough. How large?

$F_r=\mu mg \geq m\omega^2 r = F_c\implies\\\mu \geq \frac{\omega^2 r}{g}$

Let's plug in the numbers. The angular velocity should be in radians per second. We are given rev/min, which can be easily transformed by a factor 2pi/60:

$\frac{1 rev}{1 min}\cdot\frac{\frac{2\pi rad}{rev}}{\frac{60s}{1 min}}=\frac{2\pi}{60}\frac{rad}{s}$

and so 45 rev/min = 4.71 rad/s.

$\mu \geq \frac{\omega^2 r}{g}=\frac{4.71^2\frac{1}{s^2}\cdot 0.12m}{9.8\frac{m}{s^2}}=0.27$

A static coefficient of friction of at least be 0.27 must be present for the bug to continue enjoying the ride on the turntable.

3 0

3 years ago

What is a fault?

Free_Kalibri [48]

C) A crack in earth's crust where movement occurs. An example of this is the San Andreas Fault.

A) is repulsion
B) continental crust (lighter crust)
D) Hotspot

3 0

3 years ago

in which of the exercise and sports science do specialist study achievement motivation , arousal attribution and personality dev

Mekhanik [1.2K]

Sport and exercise psychology

Explanation:

Here you study the psychological factors that are connected to your performance and contribution to sport, exercises and physical activities.Through application of psychological principles you can attain higher mental health and your performance will be enhanced. For example, you will be able to recognize times when you experience emotional states without without knowing the reasons or causes which is a concept of arousal attribution.Understanding your pattern of behavior and attitude builds up your personality making you distinctive.

Learn More

Sports and exercise psychology :brainly.com/question/1213874

Keywords : exercise, sports science, study , achievement motivation, arousal attribution, personal development.

#LearnwithBrainly

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3 years ago

6. A suitcase weighing 120 N sits on a counter 1.8 m high

Liono4ka [1.6K]

Answer:

216 J

Explanation:

h = 1.8

a = 9.8

m = 12.2

GPE = HAM = 216

6 0

3 years ago

A football player runs at 8m/s and plows into a 80kg referee standing on the field causing the referee to fly forward at 5m/s. I

madreJ [45]

The topic here is momentum.

When a collision is said to be elastic, it means that the colliding objects now travel at their own new, indivual and distinct velocities, often in different directions.

So we write that as,

(mass of football player x velocity of football player) + (mass of referee x velocity of referee) = (mass of football player x velocity of football player) + (mass of referee x velocity of referee)

(M × 8) + (80 × 0) = (M× 0) + (80 × 5)

8M = 400

M = 50 kg

4 0

3 years ago