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Blababa [14]
3 years ago
11

Jane took a train traveling at an average speed of 60 mph from Boston, MA to Washington, D.C. The trip took 8 hours. On her way

back to Boston, Jane decides to take an express train that travels at an average speed of 75 mph. How long will the trip home take?
I WILL MAKE YOU BRAINLEST AND I MADE IT WORTH 50 POINTS
Mathematics
2 answers:
ira [324]3 years ago
5 0

Answer:

5 hours

Step-by-step explanation:

const2013 [10]3 years ago
5 0
The answer is 6.4 hours!!

explanation:

60 miles * 8 hours = 480 miles
75 miles * x hours = 480 miles
x hours = 480 miles / 75 miles
6.4 hours = 75 miles
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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

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Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

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If a plane crashes on the border of Mexico and the U.S, where would you bury the survivors by the law?
lyudmila [28]

Answer:

Step-by-step explanation:

So, since when do we start burying survivors alive? Did they crash into Zombiland? Was it Spirit Air who didn’t want to pay damages in law suits? Or is this a time distance question in which we have to wait until each of the surviving passengers pass away? If so then I suspect that those who survived the New Mexico/Texas border crash would be buried in the state or country in which they eventually died or where they so instructed their next of kin to bury them. Of course, maybe they would be cremated and then the ashes will sit on someone’s mantel until a house cleaner tosses them out or they ashes may be spread out over a special parcel of land or water.

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harina [27]

Answer:

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Step-by-step explanation:

Put the value where the variable is and do the arithmetic.

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Answer:

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