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Nikolay [14]
3 years ago
5

Physics help me this is idek

Physics
1 answer:
blagie [28]3 years ago
5 0
Assuming B is a stoping point that means there is acceleration because acceleration is slowing down to a stop, turning around, or speeding up. Now we also know that its speed is decreasing due to the fact that the dots are getting closser to each other. Its only velocity is it tells a direction and speed so that rules out B and C. All you have left is A and D so, you need to figure out which one has acceleration as slowing to a stop and the speed decreasing. (They kind of walk hand in hand.)

I hope that helped you.
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Https://student.masteryconnect
maria [59]

Answer:

a nucleus

Explanation:

ik.... ....... v

4 0
3 years ago
By method of dimension show that the following equation are homogenous.
il63 [147K]

Answer:

Proof in explanataion

Explanation:

The basic dimensions are as follows:

MASS = M

LENGTH = L

TIME = T

i)

Given equation is:

H = \frac{u^2Sin^2\phi}{2g}

where,

H = height (meters)

u = speed (m/s)

g = acceleration due to gravity (m/s²)

Sin Ф = constant (no unit)

So there dimensions will be:

H = [L]

u = [LT⁻¹]

g = [LT⁻²]

Sin Ф = no dimension

Therefore,

[L] = \frac{[LT^{-1}]^2}{[LT^{-2}]}\\\\\ [L] = [L^{(2-1)}T^{(-2+2)}]

<u>[L] = [L]</u>

Hence, the equation is proven to be homogenous.

ii)

F = \frac{Gm_1m_2}{r^2}\\\\

where,

F = Force = Newton = kg.m/s² = [MLT⁻²]

G = Gravitational Constant = N.m²/kg² = (kg.m/s²)m²/kg² = m³/kg.s²

G = [M⁻¹L³T⁻²]

m₁ = m₂ = mass = kg = [M]

r = distance = m = [L]

Therefore,

[MLT^{-2}] = \frac{[M^{-1}L^{3}T^{-2}][M][M]}{[L]^2}\\\\\ [MLT^{-2}] = [M^{(-1+1+1)}L^{(3-2)}T^{-2}]\\\\

<u>[MLT⁻²] = [MLT⁻²]</u>

Hence, the equation is proven to be homogenous.

8 0
3 years ago
You are given a material which produces no initial magnetic field when in free space. When it is placed in a region of uniform m
seropon [69]

Answer:

This material exhibits paramagnetism.

Explanation:

A paramagnetic material has these features: It doesn’t have any magnetic properties when placed in an external magnetic field, it gains and then loses the magnetic property as the external field is removed.

Such materials have magnetic moments oriented in random directions, thus making the net magnetic moment, zero. But when placed in an external field, they do possess a net magnetic moment. When the magnetic field is removed, they lose the magnetic property.

Thus, the material which produces no initial magnetic field when placed in a uniform magnetic field produces an additional internal magnetic field parallel to the original field. Also, it loses the magnetic properties as soon as the external magnetic field is removed. Then, the magnetism the material exhibits is paramagnetic.

7 0
3 years ago
What do you do , when you get anger?
Vera_Pavlovna [14]
I try to think of things that calms me down. If that doesn't work, I try to think of things that makes me happy. As I once read in a book, you can never get over your anger but you can calm yourself down by forgetting about it.<span />
6 0
3 years ago
Read 2 more answers
En un instante pasa por A un cuerpo con MRU de 20 m/seg, 5 segundos después pasa en su persecución, por el mismo punto A otro cu
sukhopar [10]

Answer:

Los cuerpos se encuentran luego de 15 segundos a los 300 metros.

Explanation:

El movimiento rectilíneo uniforme (MRU) es el movimiento que describe un cuerpo o partícula a través de una línea recta a velocidad constante. Es decir, que en este caso el movimiento es lineal en una única dirección  y la velocidad de desplazamiento es constante.

La posición del cuerpo después de un tiempo se calcula a partir de la posición inicial y de la velocidad del cuerpo mediante la expresión:

x=x0+v⋅t

donde:

  • x0 es la posición inicial.
  • v es la velocidad que tiene el cuerpo a lo largo del movimiento.
  • t es el intervalo de tiempo durante el cual se mueve el cuerpo.

En este caso, si el tiempo empleado por el primer cuerpo es t, el del segundo que sale 5 segundos más tarde será t-5. Siendo la velocidad del primer cuerpo 20 m/s y la del segundo cuerpo 30 m/s, entones la posición de cada uno será:

x1 = 20 m/s* t

x2 = 30 m/s* (t - 5 s)

Ambos se encuentran cuando sus posiciones son iguales:

x2=x1

30*(t - 5) = 20*t

30*t - 30*5= 20*t

30*t - 150 = 20 t

30*t - 20*t= 150

10*t= 150

t= 150÷10

t=15 segundos

Reemplazando en la expresiones de posición obtienes:

x1 = 20 m/s* 15 s= 300 m

x2 = 30 m/s* (15 s - 5 s)= 300 m

<u><em>Los cuerpos se encuentran luego de 15 segundos a los 300 metros.</em></u>

3 0
3 years ago
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