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Tems11 [23]
3 years ago
7

Calculate the molarity of a solution prepared by dissolving 11.5 g naoh in enough water to make 1.5 l of solution.

Chemistry
1 answer:
Ronch [10]3 years ago
3 0
Molar mass NaOH = 39.997 g/mol

Number of moles :

n = mass of solute / molar mass

n = 11.5 / 39.997

n = 0.287 moles

Therefore :

Molarity = moles solute / volume 

Molarity = 0.287 / 1.5 => 0.1913 M
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If you add a neutron to an atom how does it change ?
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Answer:

Its atomic mass increases by 1

An isotope of that element is fotmed with mass differences by 1

Explanation:

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2 years ago
A student has four resistors. Each resistor has a resistance of 100 ohms.
ValentinkaMS [17]

Answer:

The minimum resistance is 25 ohms.

Explanation:

Resistance of each resistor is 100 ohms. When resistors are connected in parallel, the equivalent resistance is lowest. For parallel combination, the equivalent resistance is given by :

\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+....

Here, all resistors are 100 ohms. So,

\dfrac{1}{R}=\dfrac{1}{100}+\dfrac{1}{100}+\dfrac{1}{100}+\dfrac{1}{100}\\\\R=25\ \Omega

So, the minimum resistance is 25 ohms.

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3 years ago
There are seven types of crystals. Which of these is not one of the seven?
Gelneren [198K]
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3 0
2 years ago
Read 2 more answers
13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What
rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

<em>of MgCO3.3H2O in the mixture?</em>

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

<em>Mass water:</em>

3.883g - 2.927g = 0.956g water

<em>Moles water -18.01g/mol-</em>

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

<em>Moles MgCO3.3H2O:</em>

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

<em>Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-</em>

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

<em>Mass percent:</em>

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

<h3>63.05% of MgCO3.3H2O by mass</h3>
6 0
2 years ago
You have two compounds that you have spotted on the TLC plate. One compound is more polar than the other. You ran the TLC plate
goldenfox [79]

Answer:

we will except an increase in the polarity of the system and this will cause the Non-polar spot to be near the solvent front, while the polar spot will run at an approximate speed of 0.5 Rf

Explanation:

when we run a TLC plate in a 50/50 mixture of hexanes and ethyl acetate we will except an increase in the polarity of the system and this will cause the Non-polar spot to be near the solvent front, while the polar spot will run at an approximate speed of 0.5 Rf

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3 0
3 years ago
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