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seraphim [82]
3 years ago
7

If a student calculated 0.03256 moles of copper metal (Cu0), how many grams of copper metal (Cu0) should be recovered at the end

of the experiment?
Chemistry
1 answer:
Liula [17]3 years ago
7 0

Answer:

Mass of copper metal will be 2.06756 gram

Explanation:

We have given number of moles of copper n = 0.03256

Molar mass of copper = 63.5 u

We have to calculate mass of copper metals in gram

We know that number of moles is given by number\ of\ moles=\frac{mass\ in\ gram}{molar\ mass}

0.03256=\frac{mass\ in\ gram}{63.5}

Mass in gram = 2.06756 gram

So mass of copper metal will be 2.06756 gram

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Three common gaseous compounds of nitrogen and oxygen of different elementary composition are known: (A) laughing gas containing
Ede4ka [16]

Answer:

Please find how these data prove the law of multiple proportions below

Explanation:

The law of multiple proportions was proposed by an English chemist called John Dalton. The law states that when two elements combine and to form more than one compound. The weights/masses of the second element in the two compounds, which combines with a fixed ratio of the first element, is in a simple whole number ratio.

In this question, Nitrogen is said to combine with oxygen to give three different compounds as follows:

A) laughing gas containing 63.65% nitrogen i.e. 0.6365g

This means that the mass of oxygen will be (1-0.6365) = 0.3635g

B) colorless gas containing 46.68% nitrogen i.e. 0.4668g

This means that the mass of oxygen will be 0.5332g

C) brown toxic gas containing 30.45% nitrogen i.e. 0.3045g

This means that the mass of oxygen will be 0.6955g

The ratios of oxygen in the three compounds is therefore:

0.3635: 0.5332: 0.6955

Divide this ratio by the smallest number (0.3635)

0.3635/0.3635 = 1

0.5332/0.3635 = 1.467

0.6955/0.3635 = 1.913

Multiply this ratio by 2, we have:

2: 2.9 : 3.8

Hence, the simple whole number ratio is 2:3:4.

This proves the law of multiple proportions that oxygen is in simple whole number ratio in the three different compounds.

4 0
3 years ago
. an ionic compound is composed of 34.95 g of iron and 15.05 g of oxygen. find the empirical formula of this compound.
Contact [7]

Empirical formula of ionic compound is FeO. In which the composition of atoms is 1 : 1.

Empirical formula of an ionic compound is defined as the formula which gives whole number ratio of atoms of various elements present in molecule of compund.

mass of iron in compound = 34.95 g

molar mass of iron = 55.8 g

mass of oxygen in compound = 15.05 g

molar mass of oxygen = 32 g

number of moles of iron present in the compound are ratio of mass of iron in compound/ molar mass of iron

number of moles of iron in compound= 34.95 / 55.8 = 0.6263 ~ 1

number of moles oxygen in compound= 15.05/ 32 = 0.473 ~ 0.5

the ratio of the number of oxygen atoms to number of iron atoms present in one formula unit of iron compund is 2×0.5 / 1 = 1 : 1

Hence , the required empirical formula of iron compound is FeO.

To learn more about Emiprical formula, refer:

brainly.com/question/1439914

#SPJ4

3 0
1 year ago
Heat energy is _____ when it moves from one room to another.
MArishka [77]
Hello,

Thanks for posting your question here on brainly.

There are 3 ways heat energy can move:<span> Radiation, conduction, and convection.
</span>
However, your answer to this is most likely conduction

hope this helps:)

please let me know if it's correct.



6 0
3 years ago
The Electrical conductivity of an aqueous solution depends on the concentration of which particles in the solution
anyanavicka [17]
It depends on the concentration of ions which are responsible for the electrical conductivity in aqueous solutions.
6 0
3 years ago
Read 2 more answers
1. If I have 3 identical books that all have a length of 25cm, a
Ksenya-84 [330]

Answer:

12,375 cm³

Explanation:

v=l×w×h

Since there are 3 books the equation would then be

v=3(l×w×h)

v=3(25×15×11)

v=3(4,125)

v=12,375 cm³

5 0
3 years ago
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