I might be able to. I am in 8th grade science.
Answer:
Oxygen.
Explanation:
The copper must be combined with something in the air.
Answer: <span>A-Ce is oxidized because it is losing electrons and Cu is reduced because it is gaining electrons</span><span>.
</span>There are two reactions in the equation, oxidation and reduction. A molecule that oxidized will lose electrons while the molecule that reduced will gain electrons. In this case, Cu2+ changed into Cu which means its oxidation number reduced from +2 into 0. Ce oxidation number increased from 0 into +3
- Calcium carbonate is the salt among the given options.
- Calcium carbonate ( CaCO3) can be regarded as which appears as white and odorless powder or as a colorless crystals it is insoluble in water.
- The chemical formula is CaCO3. It can be used as an antacid as well as food colouring and a food firming agent and a fertilizer.
- Calcium carbonate is calcium salt as well as carbonate salt with one-carbon compound
- Salt can be regarded as substance which is produced by reaction between acid and base. It consists negative ion (anion) of that acid as well as positive ion (cation) of the base.
- Sodium hydroxide is a base and not a salt
- Carbonic acid is an acid and not a salt
- Therefore, calcium carbonate is the only salt in the among the given options.
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Answer:
A. The pressure will increase 4 times. P₂ = 4 P₁
B. The pressure will decrease to half its value. P₂ = 0.5 P₁
C. The pressure will decrease to half its value. P₂ = 0.5 P₁
Explanation:
Initially, we have n₁ moles of a gas that occupy a volume V₁ at temperature T₁ and pressure P₁.
<em>What would happen to the gas pressure inside the cylinder if you do the following?</em>
<em />
<em>Part A: Decrease the volume to one-fourth the original volume while holding the temperature constant. Express your answer in terms of the variable P initial.</em>
V₂ = 0.25 V₁. According to Boyle's law,
P₁ . V₁ = P₂ . V₂
P₁ . V₁ = P₂ . 0.25 V₁
P₁ = P₂ . 0.25
P₂ = 4 P₁
<em>Part B: Reduce the Kelvin temperature to half its original value while holding the volume constant. Express your answer in terms of the variable P initial.</em>
T₂ = 0.5 T₁. According to Gay-Lussac's law,

<em>Part C: Reduce the amount of gas to half while keeping the volume and temperature constant. Express your answer in terms of the variable P initial.</em>
n₂ = 0.5 n₁.
P₁ in terms of the ideal gas equation is:

P₂ in terms of the ideal gas equation is:
